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DerKrebs [107]
3 years ago
12

PLEASE HELP IM STUCK. List the factors of the third term: 6n^3-n^2+5n/8-11

Mathematics
1 answer:
mafiozo [28]3 years ago
5 0

Answer:

The factors for 5 are going to be 1 and 5 or their negative counterparts, since no other whole number within the range of 5 can be multiplied to get 5.

Make sense?

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Fixed expenses are expenses that do not change from month to month, and variable expenses are expenses that can fluctuate from m
notsponge [240]

Answer:

yes

Step-by-step explanation:

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3 years ago
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The market equilibrium point for a product is reached when 12000 units are produced and sold at $27 per unit. The manufacturer w
mamaluj [8]
If the equilibrium is such that only 12000 units are sold for $27, then the total earnings from the given scenario is $324,000. The supply equation would then be,
        supply: 324000 = 6p   ; p = 324000/6 = 54000
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8 0
3 years ago
Could I please have help (3m+5)-(6+5m)
9966 [12]

Answer:

-2m -1

Step-by-step explanation:

(3m+5)-(6+5m)

Distribute the minus sign

(3m+5)-6-5m

Combine like terms

3m -5m +5 -6

-2m -1

5 0
3 years ago
HELP ME PLEASE AND THANKS
gavmur [86]
X is equal to 22.25 so all you have to do is to fill it in and find the answers
8 0
3 years ago
(5 points) An urn contains two blue balls denoted by B1 and B2, and three white balls denoted by W1, W2 and W3. One ball is draw
never [62]

Answer:

The probability of the event that first ball that is drawn is blue  is \frac 25.

Step-by-step explanation:

Probability:

If S is is an sample space in which all outcomes are equally likely and E is an event in S, then the probability of E,denoted P(E) is

P(E)=\frac{\textrm{The number of outcomes E}}{\textrm{The total number outcomes of S}}

Given that,

An urn contains two balls B₁ and  B₂ which are blue in color and W₁,W₂ and W₃ which are white in color.

Total number of ball =(2+3) =5

The number ways of selection 2 ball out of 5 ball is

=5²

=25

Total outcomes = 25

List of all outcomes in the event that the first ball that is drawn is blue are

B₁B₁ , B₁B₂ , B₁W₁ , B₁W₂ , B₁W₃ , B₂B₁ , B₂B₂ ,  B₂W₁ , B₂W₂ , B₂W₃

The number of event that the first ball that is drawn is blue is

=10.

The probability of the event that first ball that is drawn is blue  is

=\frac{10}{25}

=\frac25

3 0
3 years ago
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