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tekilochka [14]
2 years ago
7

HELP!!!!! please!!!!!

Mathematics
1 answer:
Aliun [14]2 years ago
4 0

Answer:

B

Step-by-step explanation:

-4 and 6

-4+6=2

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Help me thank you !! :)))
cupoosta [38]

Answer:

4^2+3^2=x^2

16+9=x^2

25=x^2

X=5

So the answer is 5

6 0
3 years ago
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Write two equivalent fractions for 1/4
lakkis [162]

Correct Answer:

2/8 or 4/16

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3 years ago
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Write a number or expression in each empty box to create true equations.
vova2212 [387]

Answer:

7+8

Step-by-step explanation:

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3 years ago
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How to do this?? help me please ​
alexira [117]

Answer:

sinA = 0.79        tanA = 1.3

Step-by-step explanation:

Step1:

Find the length of the line going through the middle from A to C by using pythagorean theorem.

a = 13

b = 12

c= ?

c = sqrt(a^2 + b^2)

c = sqrt(13^2 +12^2)

c = 17.69

Step 2:

Use pythagorean theorem again to find the length of the line going from A to D.

a = ?

b = 14

c = 17.69

c^2 = a^2 + b^2

Now solve for a.

a^2 = c^2 - b^2

a = sqrt(c^2 - b^2)

a = sqrt(17.69^2 - 14^2)

a = 10.81

Step 3:

Use trignometry to find the values of sinA and tanA

sinA = opposite/hypotenuse = 14/17.69 = 0.79

tanA = opposite/adjacent = 14/10.81 =1.3

3 0
2 years ago
HELP PLEASE! Will give the Brainliest if shown work!!
scZoUnD [109]

Answer:

\large\boxed{Q1.\ A_{\triangle PQR}=90\ cm^2}\\\\\boxed{Q2.\ V\approx321\ m^3}

Step-by-step explanation:

Q1.\\\\\text{If}\ \triangle ABC\sim\triangle PQR\ \text{then the quotient of the areas is equal}\\\text{the square of the similarity scale}\ k.\\\\\text{The sides}\ AB\ \text{and}\ QP\ \text{are corresponding}.\ \text{Calculate the scale:}\\\\k=\dfrac{4}{6}=\dfrac{4:2}{6:2}=\dfrac{2}{3}\\\\\text{The area of }\ \triangle ABC=40\ cm^2.\\\\\text{Let the area of}\ \triangle PQR=x,\ \text{then}\\\\\dfrac{40}{x}=\left(\dfrac{2}{3}\right)^2\\\\\dfrac{40}{x}=\dfrac{4}{9}\qquad\text{cross multiply}\\\\4x=(9)(40)\qquad\text{divide both sides by 4}\\\\x=(9)(10)\\\\x=90\ cm^2

Q2.\\\\\text{The formula of a volume of a sphere:}\\\\V=\dfrac{4}{3}\pi R^3\\\\R-radius\\\\\text{We have the diameter}\ 2R=8.5\ m\to R=\dfrac{8.5}{2}\ m=4.25\ m.\\\\\text{Substitute:}\\\\V=\dfrac{4}{3}\pi(4.25)^3=\dfrac{4}{3}\pi(76.765625)=(4)(25.588541)\pi=102.354164\pi\\\\\pi\approx3.14\\\\V=(102.354164)(3.14)\approx321\ m^3

8 0
3 years ago
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