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3 years ago

What is the volume of the sphere? (Use 3.14 for π.) 301.44 in.3 2,712.96 in.3 904.32 in.3 1,521.12 in.3

Mathematics

2 answers:

Evgesh-ka [11]3 years ago

5 0

Answer:

The volume of the sphere is 904.32 inch³.

Step-by-step explanation:

jeyben [28]3 years ago

3 0

Answer:

v=4/3ttr3

Step-by-step explanation:

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If a = 14 and b = 14, then a = b.

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2 years ago

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The speed limit is 50 miles per hour. Kyle is driving to a baseball game that starts in 2 hours. Kyle is 130 miles away from the

Marizza181 [45]

Answer: No. Kyle will arrive late

Step-by-step explanation:

The only speed limit is 50 miles per hour.

Kyle must cover 130 miles.

His travel time = 130/50 = 2.6

2 hours + (0.6 of 60 minutes )

2 hours + (36 minutes)

i.e kyle needs 2hours 36 minutes to cover 130 miles

And since the baseball starts in 2 hours, kyle will be late. Thus, the answer is No

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3 years ago

The sum of three numbers is 910. One of the numbers, x, is 60% greater than the sum of the other two numbers. What is the value

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3 years ago

Which series of transformations will not map figure H onto itself

7nadin3 [17]

Answer:

Step-by-step explanation:

Given a square with vertices at points (2,1), (1,2), (2,3) and (3,2).

Consider option A.

1st transformation $(x+0,y-2)$ will map vertices of the square into points

$(2,1)\rightarrow (2,-1);$
$(1,2)\rightarrow (1,0);$
$(2,3)\rightarrow (2,1);$
$(3,2)\rightarrow (3,0).$

2nd transformation = reflection over y = 1 has the rule (x,2-y). So,

$(2,-1)\rightarrow (2,3);$
$(1,0)\rightarrow (1,2);$
$(2,1)\rightarrow (2,1);$
$(3,0)\rightarrow (3,2)$

These points are exactly the vertices of the initial square.

Consider option B.

1st transformation $(x+2,y-0)$ will map vertices of the square into points

$(2,1)\rightarrow (4,1);$
$(1,2)\rightarrow (3,2);$
$(2,3)\rightarrow (4,3);$
$(3,2)\rightarrow (5,2).$

2nd transformation = reflection over x = 3 has the rule (6-x,y). So,

$(4,1)\rightarrow (2,1);$
$(3,2)\rightarrow (3,2);$
$(4,3)\rightarrow (2,3);$
$(5,2)\rightarrow (1,2)$

These points are exactly the vertices of the initial square.

Consider option C.

1st transformation $(x+3,y+3)$ will map vertices of the square into points

$(2,1)\rightarrow (5,4);$
$(1,2)\rightarrow (4,5);$
$(2,3)\rightarrow (5,6);$
$(3,2)\rightarrow (6,5).$

2nd transformation = reflection over y = -x + 7 will map vertices into points

$(5,4)\rightarrow (3,2);$
$(4,5)\rightarrow (2,3);$
$(5,6)\rightarrow (1,2);$
$(6,5)\rightarrow (2,1)$

These points are exactly the vertices of the initial square.

Consider option D.

1st transformation $(x-3,y-3)$ will map vertices of the square into points

$(2,1)\rightarrow (-1,-2);$
$(1,2)\rightarrow (-2,-1);$
$(2,3)\rightarrow (-1,0);$
$(3,2)\rightarrow (0,-1).$

2nd transformation = reflection over y = -x + 2 will map vertices into points

$(-1,-2)\rightarrow (4,3);$
$(-2,-1)\rightarrow (3,4);$
$(-1,0)\rightarrow (2,3);$
$(0,-1)\rightarrow (3,2)$

These points are not the vertices of the initial square.

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3 years ago