Answer:
The answer IS digital convergence.
Explanation:
80 sketches will be required. It’s just multiplication. Let x=boys and y=girls. If x=8 and y=10, then one boy has to be with one girl. In total 1 boy will be with 10 girls, so that’s 10 sketches. You do the same for boy #2 and so on. It adds up to 80.
What are the exact numbers
Answer:
The program to this question can be given as:
Program:
#include <iostream> //header file
using namespace std; //using namespace.
void SwapValues(int* userVal1, int* userVal2); //function declaration.
void SwapValues(int* userVal1, int* userVal2) //function definition.
{ //function body.
//perform swapping
int t = *userVal1;
*userVal1 = *userVal2;
*userVal2 = t;
}
int main() //main method
{
int n1, n2; //define variable
cout<<"Enter first number :"; //message
cin>>n1; //input by user.
cout<<"Enter second number :"; //message
cin>>n2; //input by user.
SwapValues(&n1,&n2); //calling function.
cout<<"Swapped values"<<endl;
cout<<"first number is :"<<n1<<endl; //print value
cout<<"second number is:"<<n2<<endl; //print value
return 0;
}
Output:
Enter first number :3
Enter second number :8
Swapped values
first number is :8
second number is :3
Explanation:
The description of the above C++ language program can be given as:
- In the program, firstly we include the header file. Then we declare and define a function that is "SwapValues()" function in the function we pass two integer variable that is "userVal1 and userVal2" inside a function, we define an integer variable that is "t" and perform swapping.
- Then we define the main function in the main function we define two variables that is "n1 and n2" this variable is used to take value-form user. then we pass this value to function and print the function values.
Answer:
The algorithm is as follows:
1. Start
2. bottles = 0
3. While bottles != 500
3.1 Create bottle
3.2 bottle = bottle + 1
4. Switch off machine
5. Stop
<em>See attachment for flowchart</em>
Explanation:
This begins the algorithm
1. Start
This initializes bottles to 0
2. bottles = 0
The loop is repeated until 500 bottles is created
3. While bottles != 500
This creates a new bottle
3.1 Create bottle
This increments the number of bottles by 1
3.2 bottle = bottle + 1
This switches of the machine after all bottles are created
4. Switch off machine
End algorithm
5. Stop
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