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anastassius [24]
2 years ago
7

.....................​

Mathematics
1 answer:
Ivahew [28]2 years ago
7 0

1.) Parallelogram

2.) Quadrilateral

3.) Complimentary

4.) bisect

5.) Supplementary

6.) GH = 14 units

7.) 80°

8.) KF = 10

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How can you determine if you need to use a combination or permutation to count the number of outcomes? Which will usually have m
Nadya [2.5K]

Answer with Step-by-step explanation:

Permutation : It is an arrangement of r elements out of n elements.

Combination : it is a selection of r element out of n elements .

Suppose we have a set

S={1,2,3}

If two elements are taken at a time then

Using permutation formula

Total number of outcomes=3P_2

Total number of outcomes=\frac{3!}{(3-2)!}

Total number of outcomes=3!=3\times 2\times1=6

Using combination formula

\binom{n}{r}=\frac{n!}{r!(n-r)!}

Total number of outcomes=\binom{3}{2}=\frac{3!}{2!1!}

Total number of outcomes=\frac{3\times2!}{2!}

Hence, total number of outcomes=3

Total number of outcomes determined by permutation have more outcomes.

Because permutation is an arrangement of elements  therefore, it consider order of arrangement of element   but combination is a selection of elements it does no consider order of elements

Arrangements of two elements out of 3 elements

{1,2},{2,3},{2,1},{3,2},{1,3},{3,1}

By using combination if two elements taken at a time then combination

{1,2},{2,3},{1,3}

4 0
3 years ago
I need help with this
eduard

Answer:are there choises?

Step-by-step explanation:

4 0
3 years ago
Factorise mx+cx+my+cy<br> With steps!!!<br> x=algebra x
avanturin [10]

Step-by-step explanation:

Hey there!

While factorising you remember to make it take common in most of the expression.

Here;

=mx+cx+my+cy

Take common 'x' in "mx+cx" and 'y' in my + cy.

= x(m+c) + y(m+c)

Now, "(m+c)" common again.

= (m+c) (x+y)

Therefore the factorized form of the expression in (m+c)(x+y).

<u>Hope it helps</u><u>.</u><u>.</u><u>.</u>

6 0
3 years ago
Read 2 more answers
√11 irrational number
andrew-mc [135]
The square root of a prime number (11) is irrational
4 0
3 years ago
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What is 6.34 when the 34 is repeating as a fraction
lana [24]

ANSWER:

6_34/99

STEP:

So yes. When a decimal is repeating, you can take the repeating number (most likely a decimal) and put 99 under it. Since 99 cannot be solved, you put 99. So, 34/99. Though we are not finished. There is still the whole 6 number left. So, you do 6_34/99.

Proof:

10x=6.6...

 -x=-0.6...

9x=6

x=6/9=1/3.

3 0
3 years ago
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