F = t ⇨ df = dt
dg = sec² 2t dt ⇨ g = (1/2) tan 2t
⇔
integral of t sec² 2t dt = (1/2) t tan 2t - (1/2) integral of tan 2t dt
u = 2t ⇨ du = 2 dt
As integral of tan u = - ln (cos (u)), you get :
integral of t sec² 2t dt = (1/4) ln (cos (u)) + (1/2) t tan 2t + constant
integral of t sec² 2t dt = (1/2) t tan 2t + (1/4) ln (cos (2t)) + constant
integral of t sec² 2t dt = (1/4) (2t tan 2t + ln (cos (2t))) + constant ⇦ answer
If we take the perimeter of the park as being equivalent to the distance that Anwar walks, then we can calculate the number of blocks he walks and then multiply this by the width of each block, thus:
Number of blocks walked = 1 + 2 + 2 + 1 + 1 + 1 = 8
Distance walked = 8*300 = 2400 feet
(You could also draw a diagram to help present this in a visual way but it is not necessary)
Answer:
Dan can buy 5 bags for 15 dollars
Step-by-step explanation:
divide 15 and 3 it will equal 5
Answer:
x = 147/5 and y = 78
Step-by-step explanation:
First solve by substitution and put 78 into y in -5x + 2y = 9 so you get 147/5
then plug 147/5 into x and find y
Answer:
f(4) =2
Step-by-step explanation:
f(x) = 2х^2 - 30,
Let x=4
f(4) = 2 (4)^2 -30
= 2*16 -30
=32-30
= 2
