The value of P(4, 6) when the two number cubes are tossed is 1/36
<h3>How to determine the probability?</h3>
On each number cube, we have:
Sample space = {1, 2, 3, 4, 5, 6}
The individual probabilities are then represented as:
P(4) =1/6
P(6) =1/6
The value of P(4, 6) when the two number cubes are tossed is:
P(4, 6) = P(4) * P(6)
This gives
P(4, 6) = 1/6 * 1/6
Evaluate
P(4, 6) = 1/36
Hence, the value of P(4, 6) when the two number cubes are tossed is 1/36
Read more about probability at:
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Answer:
Let's solve for x.
4x+5y=7
Step 1: Add -5y to both sides.
4x+5y+−5y=7+−5y
4x=−5y+7
Step 2: Divide both sides by 4.
4x/4=−5y+7/4
x=−5/4 y+ 7/4
Answer: for the first one x=−5/4 y+ 7/4
3x−2y=−12
Step 1: Add 2y to both sides.
3x−2y+2y=−12+2y
3x=2y−12
Step 2: Divide both sides by 3.
3x/3=2y−12/3
x=2/3y−4
Answer:
x=2/3y−4
Step-by-step explanation:
Answer:1 7/8
Step-by-step explanation: 5 multiplied by 3 is 15 and 15/8 and since 8 goes into 15 once with 7 left over, the answer is 1 and 7/8
Answer:
r = -3.2
Step-by-step explanation:
-0.6(r+0.2) = 1.8
Divide by -.6
-0.6/-.6(r+0.2) = 1.8/-.6
r+.2 = -3
Subtract .2 from each side
r+.2-.2 = -3-.2
r = -3.2
