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Sergeu [11.5K]
3 years ago
14

The perimeter of a square varies directly with the length of one side. what is an equation that relates the perimeter p and leng

th l of the side
Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
4 0
P=KL where K is the constant of variation
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3(x-4) = 2(-2x + 1)<br>this is confusing me​
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Answer:

x = 2

Step-by-step explanation:

<em>Distribute</em>

3 (−4) = 2 (−2+1)

3 − 12 = 2 (-2x +1)

<em>Distrubute again</em>

3x - 12 = -4x + 2

<em>Add twelve to both sides of the equation</em>

<em>Simpfly</em>

3x = -4x + 14

<em>Add 4x to both sides of the equation</em>

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7x = 14

<em>Divide both sides of the equation by the same term</em>

<em>Simpfly</em>

x = 2

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3 years ago
If the sum of three consecutive odd integers is at most 216, what is the largest possible value of one of those integers?
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Answer:

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Step-by-step explanation:

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Dima020 [189]

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The length of each side of an equilateral triangle is increased by 20%, resulting in triangle ABC. If the length of each side of
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Answer: Area of ΔABC is 2.25x the area of ΔDEF.

Step-by-step explanation: Because equilateral triangle has 3 equal sides, area is calculated as

A=\frac{\sqrt{3} }{4} a^{2}

with a as side of the triangle.

Triangle ABC is 20% bigger than the original, which means its side (a₁) measures, compared to the original:

a₁ = 1.2a

Then, its area is

A_{1}=\frac{\sqrt{3} }{4}(1.2a)^{2}

A_{1}=\frac{\sqrt{3} }{4}1.44a^{2}

Triangle DEF is 20% smaller than the original, which means its side is:

a₂ = 0.8a

So, area is

A_{2}=\frac{\sqrt{3} }{4} (0.8a)^{2}

A_{2}=\frac{\sqrt{3} }{4} 0.64a^{2}

Now, comparing areas:

\frac{A_{1}}{A_{2}}= (\frac{\sqrt{3}.1.44a^{2} }{4})(\frac{4}{\sqrt{3}.0.64a^{2} } )

\frac{A_{1}}{A_{2}} = 2.25

<u>The area of ΔABC is </u><u>2.25x</u><u> greater than the area of ΔDEF.</u>

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