Answer:
a. M_D_
: 9/16 Black furred individuals
b. M__dd
: 3/16 gray furred individuals (1/16 MMdd + 2/16 Mmdd)
c. mmD_
: 3/16 Brow-furred individuals (1/16 mmDD + 2/16 mmDd)
d. mmdd: 1/16 gray furred individuals.
Explanation:
Available data:
- Dense pigment gene, D, codes for melanophilin.
- D allele dominant over d.
- Gene M/m is responsible for the production of the pigment
- M is dominant over m
- If D is present, M/m is expressed
- If dd is present, M/m is not expressed
- DDMM, DdMM, DDMm, DdMm --->Black fur
- DDmm, Ddmm ---> Brown fur
- ddMM, ddMm -----> Light gray fur
Cross: between two dihybrids
Parental) DdMm x DdMm
Phenotype) Black-furred Black-furred
Gametes) DM, Dm, dM, dm DM, Dm, dM, dm
Punnet Square) DM Dm dM dm
DM DDMM DDMm DdMM DdMm
Dm DDMm DDmm DdMm Ddmm
dM DdMM DdMm ddMM ddMm
dm DdMm Ddmm ddMm ddmm
F1) 9/16 Black-furred individuals, D-M- (1/16 DDMM + 2/16 DDMm + 2/16
DdMM + 4/16 DdMm)
3/16 Brown-furred individuals, D-mm ( 1/16 DDmm + 2/16 Ddmm)
4/16 Gray-furred individuals, dd-- ( 1/16ddMM + 1/16 ddmm + 2/16 ddMm)
I think it’s the peregrine falcon. I’m not sure
Answer:
DNA?
I'm guessing the boys who look the same are twins, since there's no photo of them..
Hope this helps
Answer:
Modle two as it is singular, simple with a flagellum
Explanation: