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Amanda [17]
3 years ago
14

Complete the square x^2-10=16​

Mathematics
1 answer:
Hatshy [7]3 years ago
3 0

Answer:

(x - 5)² = 41

Step-by-step explanation:

* Lets revise the completing square form

- the form x² ± bx + c is a completing square if it can be put in the form

 (x ± h)² , where b = 2h and c = h²

# The completing square is x² ± bx + c = (x ± h)²

# Remember c must be positive because it is = h²

* Lets use this form to solve the problem

∵ x² - 10x = 16

- Lets equate 2h by -10

∵ 2h = -10 ⇒ divide both sides by 2

∴ h = -5

∴ h² = (-5)² = 25

∵ c = h²

∴ c = 25

- The completing square is x² - 10x + 25

∵ The equation is x² - 10x = 16

- We will add 25 and subtract 25 to the equation to make the

 completing square without change the terms of the equation

∴ x² - 10x + 25 - 25 = 16

∴ (x² - 10x + 25) - 25 = 16 ⇒ add 25 to both sides

∴ (x² - 10x + 25) = 41

* Use the rule of the completing square above

- Let (x² - 10x + 25) = (x - 5)²

∴ (x - 5)² = 41

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Answer:

Total area = 31.5 unit²

Step-by-step explanation:

Assume 1 block = 1 unit²

Divide diagram into 3 part

1. 5 by 5 block square

2. 2 by 2 block triangle(1)

2. 3 by 3 block triangle(2)

Area of square = side × side

Area of square = 5 × 5

Area of square = 25 unit²

Area of triangle(1) = [1/2][base][height]

Area of triangle(1) = [1/2][2][2]

Area of triangle(1) = 2 unit²

Area of triangle(2) = [1/2][base][height]

Area of triangle(2) = [1/2][3][3]

Area of triangle(2) = 4.5 unit²

Total area = Area of square + Area of triangle(1) +Area of triangle(2)

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The dwarves of the Grey Mountains wish to conduct a survey of their pick-axes in order to construct a 99% confidence interval ab
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Answer:

The minimum sample size needed is 125.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

For this problem, we have that:

\pi = 0.25

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

What minimum sample size would be necessary in order ensure a margin of error of 10 percentage points (or less) if they use the prior estimate that 25 percent of the pick-axes are in need of repair?

This minimum sample size is n.

n is found when M = 0.1

So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.1 = 2.575\sqrt{\frac{0.25*0.75}{n}}

0.1\sqrt{n} = 2.575{0.25*0.75}

\sqrt{n} = \frac{2.575{0.25*0.75}}{0.1}

(\sqrt{n})^{2} = (\frac{2.575{0.25*0.75}}{0.1})^{2}

n = 124.32

Rounding up

The minimum sample size needed is 125.

5 0
3 years ago
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