Looking at this problem in terms of geometry makes it easier than trying to think of it algebraically.
If you want the largest possible x+y, it's equivalent to finding a rectangle with width x and length y that has the largest perimeter.
If you want the smallest possible x+y, it's equivalent to finding the rectangle with the smallest perimeter.
However, the area x*y must be constant and = 100.
We know that a square has the smallest perimeter to area ratio. This means that the smallest perimeter rectangle with area 100 is a square with side length 10. For this square, x+y = 20.
We also know that the further the rectangle stretches, the larger its perimeter to area ratio becomes. This means that a rectangle with side lengths 100 and 1 with an area of 100 has the largest perimeter. For this rectangle, x+y = 101.
So, the difference between the max and min values of x+y = 101 - 20 = 81.
Answer:
1194 students last year
Step-by-step explanation:
The problem statement tells us ...
98% × (students last year) = 1170
Dividing by 98%, we get ...
1170/0.98 = (students last year) = 1193.88 ≈ 1194
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<em>Check</em>
1170/1194 = 0.979899... ≈ 0.98 = 98%
Answer:
1.2850
Step-by-step explanation:
Using the change of base formula,
Log 10 to base 6 = Log 10 ÷ Log 6
Log 10 = 1
Log 6 = 0.7782
Log 10 ÷ Log 6 = 1 ÷ 0.7782 = 1.2850
Answer:
go a head what can i help you with
