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Kay [80]
3 years ago
8

The admission fee at an amusement park is $2.25 for children and $5.40 for adults on a certain day 271 people enter the park and

the admission fees collected a total of $972 how many children and how many adults were admitted?
Mathematics
1 answer:
Ann [662]3 years ago
8 0

Answer:

115 adults and 156 children were admitted at the amusement park.

Step-by-step explanation:

Given that the admission fee at an amusement park is $ 2.25 for children and $ 5.40 for adults, and on a certain day 271 people enter the park and the admission fees collected a total of $ 972, to determine how many children and how many adults were admitted se you must perform the following calculation:

5.40 - 2.25 = 3.15

271 x 2.25 = 609.75

(972 - 609.75) / 3.15 = X

362.25 / 3.15 = X

115 = X

(115 x 5.40) + ((271-115) x 2.25) = X

621 + (156 x 2.25) = X

621 + 351 = X

972 = X

Thus, 115 adults and 156 children were admitted at the amusement park.

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Answer: The coefficient of terms is 2 represents length of 2 equal and opposite sides of rectangle.

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A rectangle is a 4 sides closed quadrilateral where opposite sides are equal .

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Your answer is 4.7

Using the Pythagorean Theorem, you can find the length of the missing side:

a^{2}+b^{2}=c^{2}\\(3)^{2}+b^{2}=(5.6)^{2}\\9+b^{2}=31.36\\b^{2}=22.36\\b=\pm \sqrt{22.36}
Length cannot be negative, so your answer is:
b=\sqrt{22.36}=4.728636...\\\\b=4.7
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