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Ray Of Light [21]
2 years ago
13

Find all numbers that satisfy the given condition. 1. Three less than twice the sum of a number and 6 is at most 13. 2. Five les

s than 3 times the sum of a number and 4 is at most 10. 3. Five times the sum of a number and 3 is at least 5. 4. Three times the difference between a number and 2 is at least 12. 5. The sum of 3 times a number and 8 is between 2 and 20. 6. Eight less than twice a number is between -20 and -8. 7. Four subtracted from three times some number is between -4 and 14. 8. Nine subtracted from 5 times some number is between 1 and 11.​
Mathematics
1 answer:
Dmitriy789 [7]2 years ago
5 0

Number be x

#1

\\ \sf\hookrightarrow 2(x+6)-3\leqslant=13

#2

\\ \sf\hookrightarrow 3(x+4)-5\leqslant 10

#3

\\ \sf\hookrightarrow 5(x+3)\geqslant 5

#4

\\ \sf\hookrightarrow 3(x-2)\leqslant 12

#5

\\ \sf\hookrightarrow 2\leqslant 3x+8\leqslant 20

#6

\\ \sf\hookrightarrow -20\leqslant 2x-8\leqslant -8

#7

\\ \sf\hookrightarrow -4\leqslant 3x-4\leqslant 14

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Answer:

4) -4

5) -6x-20

Step-by-step explanation:

Add x with x's and numbers with numbers

4) -6x + 9 + 6x -13

-6x+6x+9-13

x's cancel

9-13 = -4

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2 years ago
Brainliest for a math answer
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3 years ago
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Answer:

20.43% probability that a randomly chosen graduate from these 300 graduated with honors given that neither parent graduated from college.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Graduated with honors:

98 students graduated with honors. Of those, 79 had at least one parent graduating from college. So 98 - 79 = 19 did not.

Of 300 students, 207 had one or both parents graduate from college. So 300 - 207 = 93 did not have at least one parent graduating.

Find the probability that a randomly chosen graduate from these 300 graduated with honors given that neither parent graduated from college.

Of the 93 with no graduated parent, 19 earned honors

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