Answer:
a) {2/n²-7/n+9}/{8+2/n-6/n²}
b) 9/8
c) The sequence converges
Step-by-step explanation:
Given the limit of the function
limn→[infinity]2−7n+9n²/8n²+2n−6
To simplify the function given, we will have to factor out the highest power of n which is n² from the numerator and the denominator. The function will then become;
2−7n+9n²/8n²+2n−6
= n²{2/n²-7/n+9}/n²{8+2/n-6/n²}
The n² at the numerator will then cancel out the n² at the denominator to have resulting simplified equation as;
{2/n²-7/n+9}/{8+2/n-6/n²}
Evaluating the limit of the resulting equation will give;
limn→[infinity] {2/n²-7/n+9}/{8+2/n-6/n²}
Note that limn→[infinity] a/n = 0 where a is any constant.
Therefore;
limn→[infinity] {2/n²-7/n+9}/{8+2/n-6/n²}
= (0-0+9)/(8+0-0)
= 9/8
Since the limit of the sequence gives a finite value which is 9/8, thus the sequence in question is a convergent sequence.
The limit of a sequence only diverges if the limit of such sequence is an infinite value.
Answer:
One possible answer would be they sold 80 student tickets and 30 adult tickets
Step-by-step explanation:
set up two inequalities, one to show number of tickets that can be sold, and the other is how much money they need to make
5x+10y G than or = 700
x+y L than or = 110
The first inequality shows that each student (x) ticket sells for $5, and each adult (y) ticket sells for $10, and the amound has to be greater or equal to 700.
The second inequality shows that both student and adult tickets sold have to be less than or equal to 110.
First find either x or y, in this case finding y was easier
y is g than or = to 30
This means that they sold at least 30 adult tickets= $300
With y, plug into the inequality x+y L than or = to 110 to find x
x is less than or = to 80
This means that they sold at most 80 student tickets = $400
Hope this helps!
Answer:
i think teh value of each variable is 45.
Step-by-step explanation:
Answer:
Step-by-step explanation:
You may have entered the measure of a side as the measure of an angle.
You are correct. Good job!
Answer:
circle S radii SU, ST, SR
Circle U radii UT, US, UR
Step-by-step explanation:
Radii start in the middle of the circle to the end of the circle.
