Question

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Answer 1

Answer:

Q1.              $(2x-3)^{2}+3(x-4)=5+y$

$4x^{2} -12x+9+3x-12-5-y=0$

                       $4x^{2} -9x-8-y=0$

                              $4x^{2} -9x-8=y$

                                             ∴ $y = 4x^{2} -9x-8$

∴ From the quadratic equation above, a = 4, b = -9, and c = -8.

Q2.   $(x-5)^{2} -x^{2} =y$

$x^{2} -10x+25-x^{2} =y$

             $-10x+25=y$

                        ∴ $y = -10x + 25$

∴ The equation above is not a quadratic equation as it does not follow the format of ax² + bx + c.

Q3.         $2x(4x^{2} -4x+1)=y+x(8x)+4(2x)$

$8x^{3} -8x^{2} +2x-8x^{2} -8x=y$

                                   ∴ $y=8x^{3} -16x^{2} -6x$

∴ The equation above is not a quadratic equation as it does not follow the format of y = ax² + bx + c.