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2 years ago

Find m∠U. Write your answer as an integer or as a decimal rounded to the nearest tenth.

Mathematics

1 answer:

Elodia [21]2 years ago

5 0

Answer:

56.4°

Step-by-step explanation:

sin(5/6)

= 0.98511 rad = 56.443°

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Can someone help me out plz ??!

scoray [572]

Answer:

≈ 62.8

Step-by-step explanation:

Using the equal ratios of

$\frac{areaof circle}{areaofsector}$ = $\frac{circleangle}{sectorangle}$ , that is

$\frac{100\pi }{sector}$ = $\frac{2\pi }{\frac{2\pi }{5} }$ = 5, thus

5 × sector = 100π ( divide both sides by 5 )

sector = 20π = 20 × 3.14 = 62.8 units²

7 0

3 years ago

Almond trees yield 12 pounds per acre and macadamia nut trees yield 8 pounds per acre. Suppose Pippa's farm has a acres of almon

Thepotemich [5.8K]

The answer is C. 12a + 8m = 250

3 0

3 years ago

Read 2 more answers

Please solve and graph each inequality x-7<-12

Keith_Richards [23]

For this case we must resolve the following inequality:

$x-7$

Adding 7 to both sides of the inequality:

$x$

Different signs are subtracted and the major sign is placed.

$x$

Thus, the solution is given by all the values of "x" less than -5.

The solution set is: (-∞, - 5)

Answer:

$x$

See attached image

3 0

3 years ago

615.44 rounded to the nearest tenth

Whitepunk [10]

The answer is 615.4

Hope this helps :)

5 0

3 years ago

Read 2 more answers

rotation of 90 degrees counterclockwise about the origin, point O, then a reflection across the x-axis reflection across the y-a

SpyIntel [72]

Answer:

The point O can be (x,y) or (-x,y) or (-x,-y) or ( x,-y) reason being that you haven't given point O lies in which quadrant.

Rotation through 90° counter clockwise

(x,y) = (-y,x)

(-x,y)=(-y,-x)

(-x,-y)=(y,-x)

(x,-y) =(y,x)

Then Reflection across X axis has taken place.

(-y,x) = (-y,-x)

(-y,-x)=(-y,x)

(y,-x)=(y,x)

(y,x)=(y,-x)

Then a reflection across the y-axis has taken place.

(-y,-x)=(y,-x)

(-y,x) = (y,x)

(y,x) =(-y,x)

(y,-x)=(-y,-x)

Then a translation a units to the right and b units up has taken place.

(y,-x)=(y+a,-x+b)

(y,x) =(y+a, x+b)

(-y,x) =(-y+a,x+b)

(-y,-x)=(-y+a,-x+b)

Then a rotation of 180 degrees counterclockwise about the origin has taken place.

(y+a,-x+b)=[-(y+a),-(-x+b)]

(y+a, x+b)=[- (y+a), -(x+b)]

(-y+a,x+b)=[-(-y+a),-(x+b)]

(-y+a,-x+b) =[-(-y+a),-(-x+b)]

Now Again a reflection across the Y axis has taken place.

[-(y+a),-(-x+b)]=[(y+a),-(-x+b)]

[-(y+a),-(x+b)]=[(y+a),-(-x+b)]

[-(-y+a),-(x+b)]=[(-y+a),-(x+b)]

[-(-y+a),-(-x+b)]=[(-y+a),-(-x+b)]

Totally depends on value of a and b on which quadrant these point lies.

7 0

3 years ago