2 years ago

PLEASE GUYS I NEED HELP!! IS THERE ANYONE WHO KNOW THIS TWO QUESTIONS :')))

Mathematics

1 answer:

Arturiano [62]2 years ago

3 0

Answer:

figure it out your self stop having other people do your work for you

Step-by-step explanation:

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4+2(x+7)=26 does any body know what it is

aliina [53]

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Step-by-step explanation:

Distribute the 2 to the X and 7

4+2x+14=26

2x+18 =26

minus the 18 from 26

2x = 8

divide 2x and 8 by 2

X= 4

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3 years ago

Carrie needs to determine the number of tiles that will fit in each row along the back of the shower. If the back of the shower

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You need to add the dimensions

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4 years ago

The Star Wars franchise was purchased for $1,000,000,000 in 2015. If the value of the franchise increases 2% each year, which eq

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Step-by-step explanation:

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3 years ago

Find the bases for Col A and Nul A, and then state the dimension of these subspaces for the matrix A and an echelon form of A b

Rainbow [258]

Answer:

skip counting by 0

Step-by-step explanation:

skipcount by 0 to get to 100 for the third column.

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4 years ago

Use the Ratio Test to determine whether the series is convergent or divergent. [infinity] n! 112n n = 1 Identify an. Correct: Yo

MakcuM [25]

Answer:

Step-by-step explanation:

Recall that the ratio test is stated as follows:

Given a series of the form $\sum_{n=1}^{\infty} a_n let L=\lim_{n\to \infty}\left|\frac{a_{n+1}}{a_n}\right|$

If L<1, then the series converge absolutely, if L>1, then the series diverge. If L fails to exist or L=1, then the test is inconclusive.

Consider the given series $\sum_{n=1}^{\infty} n! \cdot 112n$ . In this case, $a_n =n! \cdot 112n$ , so , consider the limit

$\lim_{n\to\infty} \frac{(n+1)! 112 (n+1)}{n! 112 n} = \lim_{n\to\infty}\frac{(n+1)^2}{n}$

Since the numerator has a greater exponent than the numerator, the limit is infinity, which is greater than one, hence, the series diverge by the ratio test

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4 years ago

PLEASE GUYS I NEED HELP!! IS THERE ANYONE WHO KNOW THIS TWO QUESTIONS :')))​

PLEASE GUYS I NEED HELP!! IS THERE ANYONE WHO KNOW THIS TWO QUESTIONS :')))