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7nadin3 [17]
3 years ago
14

NIE

Mathematics
1 answer:
Vaselesa [24]3 years ago
4 0

Hi!

Please see the attached image for your answer with explanation.

Have a great day!

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One bag contains three white marbles and five black marbles, and a second bag contains four white marbles and six
sergeinik [125]

Hmm I think this is 1/2

Sorry if I'm wrong I'm not the best at math

8 0
3 years ago
Which equation does not represent a direct variation?
tatuchka [14]
Okay I think there has been a transcription issue here because it appears to me there are two answers. However I can spot where some brackets might be missing, bear with me on that.

A direct variation, a phrase I haven't heard before, sounds a lot like a direct proportion, something I am familiar with. A direct proportion satisfies two criteria:

The gradient of the function is constant s the independent variable (x) varies

The graph passes through the origin. That is to say when x = 0, y = 0.

Looking at these graphs, two can immediately be ruled out. Clearly A and D pass through the origin, and the gradient is constant because they are linear functions, so they are direct variations.

This leaves B and C. The graph of 1/x does not have a constant gradient, so any stretch of this graph (to y = k/x for some constant k) will similarly not be direct variation. Indeed there is a special name for this function, inverse proportion/variation. It appears both B and C are inverse proportion, however if I interpret B as y = (2/5)x instead, it is actually linear.

This leaves C as the odd one out.

I hope this helps you :)
4 0
3 years ago
At what angle does a diffraction grating produce a second-order maximum for light having a first-order maximum at 20.0 degrees?
hichkok12 [17]

Answer:

At 43.2°.

Step-by-step explanation:

To find the angle we need to use the following equation:

d*sin(\theta) = m\lambda

Where:

d: is the separation of the grating

m: is the order of the maximum

λ: is the wavelength

θ: is the angle              

At the first-order maximum (m=1) at 20.0 degrees we have:

\frac{\lambda}{d} = \frac{sin(\theta)}{m} = \frac{sin(20.0)}{1} = 0.342

Now, to produce a second-order maximum (m=2) the angle must be:

sin(\theta) = \frac{\lambda}{d}*m

\theta = arcsin(\frac{\lambda}{d}*m) = arcsin(0.342*2) = 43.2 ^{\circ}

Therefore, the diffraction grating will produce a second-order maximum for the light at 43.2°.    

I hope it helps you!                                                        

6 0
3 years ago
<br> .........help.......me.......please
AlexFokin [52]

Answer:

s

Step-by-step explanation:

4 0
3 years ago
I need help with this graph.
tatuchka [14]
Two parallel lines never intersect, therefore they will never have a solution.

One line could be x=6 and the other could be x=2

Hope this helps :)
3 0
4 years ago
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