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Delicious77 [7]
2 years ago
15

Prove that 1/sec0-tan0= sec0+tan0

Mathematics
1 answer:
Leviafan [203]2 years ago
7 0

Answer:

Step-by-step explanation:

\text{LHS}=\frac{1}{\sec \theta-\tan \theta}\\=\frac{\sec \theta+\tan \theta}{(\sec \theta-\tan \theta)(\sec \theta+\tan \theta)}\\=\frac{\sec \theta+\tan \theta}{\sec^{2} \theta-\tan^{2} \theta}\\=\frac{\sec \theta+\tan \theta}{1}\\=\sec \theta+\tan \theta\\=\text{RHS}

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Answer:

The question is asking for the perimeter. There are three ways to answer this depending on the assumptions though so I'll let you choose.

Assumptions are basically the different scenarios

1st scenario being the trim covers the carpet and the tile, they'd need 48m of trim (12+12+4+8+8+4)

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Step-by-step explanation:

trim is just the perimeter since it covers the base of the wall

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