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2 years ago

I need the answers for 6 & 7 i will give brainlist:)!! PLEASEEEE

Mathematics

1 answer:

scZoUnD [109]2 years ago

6 0

Answer:

6: m = 25 + 5x; m is the money made and x is the amount of chores done.

6b: m(4) = 25 + 5(4) = 25 + 20 = 45; m(4) = 45

7: c = 175 - 6x; c is the amount of cards Mason owns, x is the amount of months

7b: c(7) = 175 - 6(7) = 175 - 42 = 133; c(7) = 133

To make the equation, just find the starting value and then add in the amount of change that occurs in that number.

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A television normally sells for $320. This week, it's on sale at 60% off the normal price. What is the sale price?

shutvik [7]

If it is 60% off, then u r actually paying 40%
so ur paying 40% of 320....turn ur percent to a decimal..." of " means multiply

so the sale price is : 0.40(320) = $ 128 <==

or u could also do it this way...
320 - 0.60(320) = 320 - 192 = $ 128 <==

4 0

2 years ago

Read 2 more answers

Solve: 46, 56, 67, 78, 34, 46, 57 mean: Range: Median: Mode:

Serhud [2]

Answer:

mean:54.857142857143

Range:44

median:56

mode:46

5 0

2 years ago

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4. Dean Pelton wants to perform calculations to impress the accreditation consultants, but upon asking for information about GPA

Leya [2.2K]

Answer:

the minimum records to be retrieved by using Chebysher - one sided inequality is 17.

Step-by-step explanation:

Let assume that n should represent the number of the students

SO, $\bar x$ can now be the sample mean of number of students in GPA's

To obtain n such that $P( \bar x \leq 2.3 ) \leq .04$

⇒ $P( \bar x \geq 2.3 ) \geq .96$

However ;

$E(x) = \int\limits^4_2 Dx (2+e^{-x} ) 4x = D \\ \\ = D(e^{-x} (e^xx^2 - x-1 ) ) ^D_2 = 12.314 D$

$E(x^2) = D\int\limits^4_2 (2+e^{-x})dx \\ \\ = \dfrac{D}{3}[e^{-4} (2e^x x^3 -3x^2 -6x -6)]^4__2}}= 38.21 \ D$

Similarly;

$D\int\limits^4_2(2+ e^{-x}) dx = 1$

⇒ $D*(2x-e^{-x} ) |^4_2 = 1$

⇒ $D*4.117 = 1$

⇒ $D= \dfrac{1}{4.117}$

$\mu = E(x) = 2.991013 ; \\ \\ E(x^2) = 9.28103$

∴ $Var (x) = E(x^2) - E^2(x) \\ \\ = .3348711$

Now; $P(\bar \geq 2.3) = P( \bar x - 2.991013 \geq 2.3 - 2.991013) \\ \\ = P( \omega \geq .691013) \ \ \ \ \ \ \ \ \ \ (x = E(\bar x ) - \mu)$

Using Chebysher one sided inequality ; we have:

$P(\omega \geq -.691013) \geq \dfrac{(.691013)^2}{Var ( \omega) +(.691013)^2}$

So; $(\omega = \bar x - \mu)$

⇒ $E(\omega ) = 0 \\ \\ Var (\omega ) = \dfrac{Var (x_i)}{n}$

∴ $P(\omega \geq .691013) \geq \dfrac{(.691013)^2}{\frac{.3348711}{n}+(691013)^2}$

To determine n; such that ;

$\dfrac{(.691013)^2}{\frac{.3348711}{n}+(691013)^2} \geq 0.96 \\ \\ \\ (.691013)^2(1-.96) \geq \dfrac{-3348711*.96}{n}$

⇒ $n \geq \dfrac{.3348711*.96}{.04*(.691013)^2}$

$n \geq 16.83125$

Thus; we can conclude that; the minimum records to be retrieved by using Chebysher - one sided inequality is 17.

5 0

2 years ago

There are 3 yellow, 4 blue, 3 green, and 2 red candies in a bag. Without looking, Brian reaches into the bag and pulls out one p

olga55 [171]

<h3> - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - </h3>

➷ First, we need to figure out the total number of candies:

3 + 4 + 3 + 2 = 12

Keep this number in mind as it will be the denominator

There are 3 yellow candies so the probability would be:

$\frac{3}{12}$ or $\frac{1}{4}$

➶Hope This Helps You!

➶Good Luck :)

➶Have A Great Day ^-^

↬ Hannah ♡

7 0

2 years ago

If the outliers are not included, what is the mean of the data set?

ioda

If you don't include the outlier (50) then it is 79.7

4 0

2 years ago

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