Hello from MrBillDoesMath!
Answer:
Domain: x >=0 for both cases
Discussion:
Assuming we are dealing with real valued functions, the domain of
y = x^(1/2) +4
is the set of all "x" such that x>= 0 (so we are taking the square root of a positive, or zero, real number)
The domain of x^(1/2) +6 -7 is the same as for the last function and for the same reason.
Thank you,
MrB
We can't see the whole question :/
Answer:
Option 3) -6,-5/2
Step-by-step explanation:
we know that
The formula to solve a quadratic equation of the form
is equal to
in this problem we have
so
substitute in the formula
Hello :
let the slope : a and ; b the slope of the line : 5x - 3y = 8
<span>the line that is perpendicular to 5x-3y=8 so : a×b = - 1
but :
5x - 3y = 8... y = (5/3)x - 8/3 when : b = 5/3
</span><span> the slope intercept form of the equation of the line that is perpendicular
to 5x-3y=8 is : y = (5/3)x +c </span>
