All categories

3 years ago

7003 divided by 5 show work :)

Mathematics

2 answers:

Oliga [24]3 years ago

8 0

Answer:

1400.8

Step-by-step explanation:

5/7003

1. 7-5 (5 goes in once)

2. you can't do 2-5 so drop down the 0. (20)

3. 5 goes into 20 4 times. add the 4 to the top

4. put the zero in since it doesn't go with anything (it should look like 1400)

5. drop the 3 down but since 5 can't go in add a zero (and a decimal to your answer on top) - 1400.

6. 5 goes into 30, 8 times.

7. final answer: 1400.8

Likurg_2 [28]3 years ago

3 0

Answer:

1400.6

Step-by-step explanation:

7003 divided into 5 groups puts 1400.6 in each group

You might be interested in

ANSWER ASASPP PLSSSSSS

podryga [215]

Answer:

There are 14 problems worth 5 points and 15 problems worth 2 points.

Step-by-step explanation:

Hope this helped have a good day :)

5 0

2 years ago

What is the value of x?

Hitman42 [59]

I believe the value of x would be 20.

3 0

3 years ago

A solar powered water pumping system in Desert Range, Utah, has six solar panels, each containing 6 rows modules. Each row has 6

Reil [10]

36 modules
6modulesx6modules=36midules

6 0

3 years ago

13. Dave wants to buy a ceramic vase. The sale price is £3.

Irina-Kira [14]

Answer:

0.7x=3

divide by 0.7

x=4.28

Hope This Helps!!!

6 0

3 years ago

Evaluate the following when $a = 3$, $b = \frac14$, and $c = 5$: \[ \frac{b^{-1}}{ca^{-1} - ac^{-1}}. \] Thank you so much!

pickupchik [31]

$\dfrac{b^{-1}}{ca^{-1}-ac^{-1}}=\dfrac{\frac1b}{\frac ca-\frac ac}$

Multiply the numerator and denominator by $ac$ :

$\dfrac{\frac1b}{\frac ca-\frac ac}\cdot\dfrac{ac}{ac}=\dfrac{\frac{ac}b}{c-a}$

Since $b=\frac14$ , we have $b^{-1}=\frac1b=4$ . So substituting the values of a, b, and c gives us

$\dfrac{\frac{ac}b}{c-a}=\dfrac{3\cdot5\cdot4}{5-3}=\dfrac{60}2=\boxed{30}$

4 0

3 years ago

Read 2 more answers