Quantity of cheerios cereal in the smaller box Hannaford sold = 9 ounces
Cost of nine ounces of cheerios cereal = $2.50
Cost of one ounce of cheerios cereal :
Cost of one ounce of cheerios cereal in the smaller box = $0.27
Quantity of cheerios cereal in the larger box Hannaford sold = 20 ounces
Cost of nine ounces of cheerios cereal = $3.79
Cost of one ounce of cheerios cereal :
Cost of one ounce of cheerios cereal in the larger box = $0.18
Difference in their cost per ounce :
Therefore, the difference in cost in dollars per ounce between the two sizes = $0.09
The number (62/495) is a rational number because it is a ratio between 62 and 495
And, 62 ÷ 495 = 0.1252525252525252525252............
So, Its equivalent decimal notation is a repeating decimal number
The length of the function y = 3x over the given interval [0, 2] is 3.2 units
For given question,
We have been given a function y = 3x
We need to find the length of the function on the interval x = 0 to x = 2.
Let f(x) = 3x where f(x) = y
We have f'(x) = 3, so [f'(x)]² = 9.
Then the arc length is given by,
![\int\limits^a_b {\sqrt{1+[f'(x)]^2} } \, dx\\\\= \int\limits^2_0 {\sqrt{1+9} }\, dx\\\\=\sqrt{10}\\\\ =3.2](https://tex.z-dn.net/?f=%5Cint%5Climits%5Ea_b%20%7B%5Csqrt%7B1%2B%5Bf%27%28x%29%5D%5E2%7D%20%7D%20%5C%2C%20dx%5C%5C%5C%5C%3D%20%5Cint%5Climits%5E2_0%20%7B%5Csqrt%7B1%2B9%7D%20%7D%5C%2C%20dx%5C%5C%5C%5C%3D%5Csqrt%7B10%7D%5C%5C%5C%5C%20%3D3.2)
This means, the arc length is 3.2 units.
Therefore, the length of the function y = 3x over the given interval [0, 2] is 3.2 units
Learn more about the arc length here:
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Answer:
y = -2x + 4
Step-by-step explanation:
y = mx + b
m ---> slope
b ----> y-intercept
y = -2x + 4
Answer:
6 Dollars.
Step-by-step explanation:
A toolset sells for $150 at a local hardware store. The toolset is on sale for 20% off the retail price, p, given by f(p) = 0.80p. Devon is interested in buying the toolset and has a coupon for $30 off the price of the toolset, which can be represented by g(p) = p – 30.
Therefore, the cost of using the coupon followed by the discount,
f[g(p)] = 0.80(p - 30) = 0.80(150 - 30) = 96 dollars.
And the cost of using the discount followed by the application of the coupon,
g[f(p)] = 0.80p - 30 = 0.80 × 150 - 30 = 90 dollars.
Therefore, the difference between f[g(p)] and g[f(p)] is (96 - 90 ) = 6 dollars. (Answer)
