Let A(4,12) and B(6,18)
RATE OF CHANGE = m = (y₂ - y₁) / (x₂ - x₁) = (18-12)/ (6-4)
m= 6/2 or m = 3
The value of integration of y=16-
from x=-1 to x=1 is 94/3.
Given the equation y=16-
and the limit of the integral be x=-1,x=1.
We are required to find the value of integration of y=16-
from x=-1 to x=1.
Equation is relationship between two or more variables that are expressed in equal to form.Equation of two variables look like ax+by=c.It may be linear equation, quadratic equation, or many more depending on the power of variable.
Integration is basically opposite of differentiation.
y=16-
Find the integration of 16-
.
=16x-
Now find the value of integration from x=-1 to x=1.
=16(1)-
-16(-1)-
=16(1)-1/3+16-1/3
=32-2/3
=(96-2)/3
=94/3
Hence the value of integration of y=16-
from x=-1 to x=1 is 94/3.
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Answer:
uh 1 pound per day 16 pounds so 16 days, i guess
Step-by-step explanation:
Answer: The average was 9 years old find the average age of both groups is 10 years old.
Step-by-step explanation:
Formula foe average : 
Given : The first group of students consists of 10 and their average age was 13 years old.
i.e.
(1)
The next group consisted of 30 students and their average was 9 years old.
i.e.
(2)
Then from (1) and (2) , the sum of both groups (first group and next group )students = 130+270 =400
Combined students of both groups (first and next group )= 10+30=40
Now , the average of both groups =

Hence, the average was 9 years old find the average age of both groups is 10 years old.
Answer: dude i wanna help you soooo bad but my stupid computar wont let me see the image can you say the question so i can try?
Step-by-step explanation: