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RUDIKE [14]
3 years ago
7

HELP? 7-15 please :) show work thank you!

Mathematics
1 answer:
Alexus [3.1K]3 years ago
7 0

Answer:

7. x = 3

Step-by-step explanation:

To find the value of x, use the triangle sum property. Every triangle has interior angles which add to 180 degrees. To solve, add the expressions and numbers together then set equal to 180. Then use inverse operations to solve for x.

7. 20x - 9 + 10x + 9 + 90 = 180             Subtract 90 from both sides.

   20x - 9 + 10x + 9 = 90                       Add -9 + 9 = 0

   20x + 10x = 90                                  Add like terms 20x + 10x = 30x

   30x = 90                                            Divide both sides by 30.

        x = 3

Repeat this process for each problem.

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The value of integration of y=16-x^{2} from x=-1 to x=1 is 94/3.

Given the equation y=16-x^{2} and the limit of the integral be x=-1,x=1.

We are required to find the value of integration of y=16-x^{2} from x=-1 to x=1.

Equation is relationship between two or more variables that are expressed in equal to form.Equation of two variables look like ax+by=c.It may be linear equation, quadratic equation, or many more depending on the power of variable.

Integration is basically opposite of differentiation.

y=16-x^{2}

Find the integration of 16-x^{2}.

=16x-x^{3}/3

Now find the value of integration from x=-1 to x=1.

=16(1)-(1)^{3}/3-16(-1)-(-1)^{3}/3

=16(1)-1/3+16-1/3

=32-2/3

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Hence the value of integration of y=16-x^{2} from x=-1 to x=1 is 94/3.

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4 0
1 year ago
Hao bought a 16-pound bag of dog food. If his dog eats pound of food every day, for how many days will the bag of dog food last?
densk [106]

Answer:

uh 1 pound per day 16 pounds so 16 days, i guess

Step-by-step explanation:

3 0
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the first group of students consists of 10 and their average age was 13 years old the next group consisted of 30 students and th
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Answer: The average was 9 years old find the average age of both groups is 10 years old.

Step-by-step explanation:

Formula foe average : \text{Average} =\dfrac{\text{Sum of all observations}}{\text{Number of observations}}

Given : The first group of students consists of 10 and their average age was 13 years old.

i.e. 13=\dfrac{\text{Sum of ages of students of first group}}{10}\\\\\Rightarrow\ \text{Sum of ages of students of first group}=13\times10=130      (1)

The next group consisted of 30 students and their average was 9 years old.

i.e. 9=\dfrac{\text{Sum of ages of students of next group}}{30}\\\\\Rightarrow\ \text{Sum of ages of students of nextgroup}=9\times30=270      (2)

Then from (1) and (2) , the sum of both groups (first group and next group )students = 130+270 =400

Combined students of both groups (first and next group )= 10+30=40

Now , the average of both groups =\dfrac{\text{Sum of combined students}}{\text{combined students}}

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Hence, the average was 9 years old find the average age of both groups is 10 years old.

4 0
3 years ago
Helpppp me plzzzzzz<br>​
siniylev [52]

Answer: dude i wanna help you soooo bad but my stupid computar wont let me see the image can you say the question so i can try?

Step-by-step explanation:

6 0
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