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3 years ago

Which shows the equation below written in the form ax2 + bx + c = 0?

2 answers:

6 0

X + 9 = 2 ( x - 1 )²
x + 9 = 2 ( x² - 2 x + 1 )
x + 9 = 2 x² - 4 x + 2
- 2 x² + 4 x + x - 2 + 9 = 0
- 2 x² + 5 x + 7 = 0 / * ( -1 )
Answer:
A ) 2 x² - 5 x - 7

nikitadnepr [17]3 years ago

6 0

Answer:

Option A is correct

$2x^2-5x-7=0$

Step-by-step explanation:

Given the equation:

$x+9=2(x-1)^2$

Using identity:

$(a-b)^2=a^2-2ab+b^2$

then;

$x+9 = 2(x^2-2x+1)$

Using distributive property: $a \cdot (b+c) = a\cdot b+ a\cdot c$

$x+9 = 2x^2-4x+2$

Subtract x from both sides we have;

$9= 2x^2-5x+2$

Subtract 9 from both sides we have;

$0=2x^2-5x-7$

$2x^2-5x-7=0$

Therefore, the equation $2x^2-5x-7=0$ is written in the form of $ax^2+bx+c=0$

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However, let's prove in a more formal way that

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Secondly, it is trivially surjective: the matrix

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is clearly the image of the real number x.

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Answer:

The solution is:

$x=4$

Step-by-step explanation:

Considering the expression

$lne^{lnx}+lne^{lnx}^{^2}=2ln8$

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$\mathrm{Apply\:log\:rule}:\quad \:log_a\left(a^b\right)=b$

$\ln \left(e^{\ln \left(x\right)}\right)=\ln \left(x\right),\:\space\ln \left(e^{\ln \left(x\right)2}\right)=\ln \left(x\right)2$

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Because

$\ln \left(8\right)$

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So, equation A becomes

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$x=4$

Therefore, the solution is

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