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Olin [163]
3 years ago
7

Which shows the equation below written in the form ax2 + bx + c = 0?

Mathematics
2 answers:
GalinKa [24]3 years ago
6 0
X + 9 = 2 ( x - 1 )²
x + 9 = 2 ( x² - 2 x + 1 )
x + 9 = 2 x² - 4 x + 2
- 2 x² + 4 x + x - 2 + 9 = 0
- 2 x² + 5 x + 7 = 0   / * ( -1 )
Answer:
A ) 2 x² - 5 x - 7 
nikitadnepr [17]3 years ago
6 0

Answer:

Option A is correct

2x^2-5x-7=0

Step-by-step explanation:

Given the equation:

x+9=2(x-1)^2

Using identity:

(a-b)^2=a^2-2ab+b^2

then;

x+9 = 2(x^2-2x+1)

Using distributive property: a \cdot (b+c) = a\cdot b+ a\cdot c

x+9 = 2x^2-4x+2

Subtract x from both sides we have;

9= 2x^2-5x+2

Subtract 9 from both sides we have;

0=2x^2-5x-7

or

2x^2-5x-7=0

Therefore, the equation 2x^2-5x-7=0 is written in the form of ax^2+bx+c=0

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