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max2010maxim [7]
2 years ago
10

A box has 3 one-dollar bills, 2 five-dollar bills, 2 ten-dollar bills, and 1 twenty-dollar bill. A student selects one bill from

the box at random.
PART A Develop a probability model to compare the probability of selecting $5 to the probability of selecting $10. Explain.
PART B how does the probability of selecting $1 compare to the probability of selecting $20? explain​
Mathematics
1 answer:
ExtremeBDS [4]2 years ago
8 0

Answer and explanation:

There's 3 one dollar bills

2 five dollar bills

and 2 ten dollar bills

and 1 twenty dollar bill

3+2+2+1=8

Part A: The probability of selecting 5 is 2/8 and the probability of selecting 10 is also 2/8 and both of them are the same, 1/4.

Part B: The probability of selecting a one dollar bill is 3/8 and the probability of selecting a twenty dollar bill is 1/8 because there are 3 one dollar bills in 8 bills and 1 twenty one dollar bill in 8 bills only.

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Step-by-step explanation:

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3 years ago
A metallurgist has one alloy containing 34% copper another containing 48% copper. How many pounds of each alloy must he use to m
Zielflug [23.3K]

Answer:

<h2>36.14 pounds of 34% copper alloy and 9.86 pounds of 48% copper alloy</h2>

Step-by-step explanation:

        First alloy contains 34% copper and the second alloy contains 48% alloy.

We wish to make 46 pounds of a third alloy containing 37% copper.

       Let the weight of first alloy used be x in pounds and the weight of second alloy used be y in pounds.

       Total weight = 46\text{ }pounds=x+y        -(i)

      Total weight of copper = 37\%\text{ of 46 pounds = }34\%\text{ of }x\text{ pounds + }48\%\text{ of }y\text{ pounds }

       \dfrac{37\times 46}{100}=\dfrac{34x}{100}+\dfrac{48y}{100}\\\\ 34x+48y=1702        -(ii)

       Subtracting 34 times first equation from second equation,

34x+48y-34x-34y=1702-34\times46\\14y=138\\y=9.857\text{ }pounds \\x=36.143\text{ }pounds

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Third system:  infinitely many solutions, since the second equation is a multiple of the first

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