Answer:
and 
Step-by-step explanation:
We must solve the quadratic equation to find the values of x that satisfy equality
Subtract 24 on both sides of equality
Now we factor the quadratic equation
Identify two numbers that when you add them you get as a result 2 and when you multiply them you get as a result -24
The numbers sought are: 6 and -4
So the factors are:
Finally note that the solutions are:
and
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Answer:
7.2
Step-by-step explanation:
Distance between (4, 3) and (8, 9):
(nearest tenth)
Hello!
Vertical asymptotes are determined by setting the denominator of a rational function to zero and then by solving for x.
Horizontal asymptotes are determined by:
1. If the degree of the numerator < degree of denominator, then the line, y = 0 is the horizontal asymptote.
2. If the degree of the numerator = degree of denominator, then y = leading coefficient of numerator / leading coefficient of denominator is the horizontal asymptote.
3. If degree of numerator > degree of denominator, then there is an oblique asymptote, but no horizontal asymptote.
To find the vertical asymptote:
2x² - 10 = 0
2(x² - 5) = 0
(x - √5)(x + √5) = 0
x = √5 and x = -√5
Graphing the equation, we realize that x = -√5 is not a vertical asymptote, so therefore, the only vertical asymptote is x = √5.
To find the horizontal asymptote:
If the degree of the numerator < degree of denominator, then the line, y = 0 is the horizontal asymptote.
Therefore, the horizontal asymptote of this function is y = 0.
Short answer: Vertical asymptote: x = √5 and horizontal asymptote: y = 0
1)
2x-y=16
-2y-x=-8
You need to solve on of the equations for x or y. I will solve the first equation for y.
2x-y=16
-y=-2x+16
y=+2x-16
Then you can substitute that y value for the y value in the second equation (2y-x=-8) can be written as 2(2x-16)-x=-8 since y=2x-16.
then you solve for x.
4x-32-x=-8
3x=24
x=8
therefore y=0 since 2(0)-8=-8
I will complete the second part of the question either in the comments or a new answer later when I have more time.
