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Rashid [163]
3 years ago
10

The vertex of the graph of y=(x-1)^2-5 is

Mathematics
2 answers:
zaharov [31]3 years ago
7 0
For y  = (x-h)^2 + k
the vertex is h,k

comparing<span>
y=(x-1)^2-5</span>  with  y  = (x-h)^2 + k

we have h = 1, k = -5

so the vertex of y=(x-1)^2-5  is  (1,-5)

lorasvet [3.4K]3 years ago
4 0

Answer:

(1,-5)

Step-by-step explanation:

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3 years ago
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grin007 [14]

Step-by-step explanation:

We have,

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3 years ago
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vitfil [10]
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5 0
3 years ago
Really need help! Brainliest to correct!
zlopas [31]

Answer:

<u>Given</u>:

  • R(x) = 59x - 0.3x²
  • C(x) = 3x + 14

<u>Find the following</u>:

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7 0
2 years ago
Y=-7 + 2x how to graph
blondinia [14]
I know for 2x you would go up 2 over 1 but I don’t know about -7?? Maybe down
8 0
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