The vertex of the graph of y=(x-1)^2-5 is
2 answers:
For y = (x-h)^2 + k
the vertex is h,k
comparing<span>
y=(x-1)^2-5</span> with y = (x-h)^2 + k
we have h = 1, k = -5
so the vertex of y=(x-1)^2-5 is (1,-5)
Answer:
(1,-5)
Step-by-step explanation:
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