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3 years ago

The vertex of the graph of y=(x-1)^2-5 is

2 answers:

7 0

For y = (x-h)^2 + k
the vertex is h,k

comparing<span>
y=(x-1)^2-5</span> with y = (x-h)^2 + k

we have h = 1, k = -5

so the vertex of y=(x-1)^2-5 is (1,-5)

lorasvet [3.4K]3 years ago

4 0

Answer:

(1,-5)

Step-by-step explanation:

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Please help with this

omeli [17]

Answer:

$y = \frac{1}{8} x - 3$

Step-by-step explanation:

Formula for straight lines:

$y = mx + b$

where m = slope, b = constant

Given:

y-intercept = -3 (0, -3)

m = ⅛

Substitute into formula to find b.

$- 3 = \frac{1}{8} (0) + b \\ - 3 = 0 + b \\ b = - 3$

Substitute b into original formula

$y = mx + b \\ y = \frac{1}{8} x + ( - 3) \\ y = \frac{1}{8} x - 3$

4 0

3 years ago

"use the graph to determine the limit if it exists" limit x -> 3 I provided graph below

bekas [8.4K]

Answer:

im not sure but probably 18

Step-by-step explanation:

5 0

4 years ago

Is anyone able to give a step by step process to this?

Thepotemich [5.8K]

Answer:

The value of y is 3 cm.

Step-by-step explanation:

Given,

Perimeter of triangle = $29\ cm$

Solution,

Lets redraw the triangle with nomenclature ABC, given in the attachment.

∴P(ΔABC) = 29 cm (P stands for perimeter)

Length of AB = $y+9$

Length of BC = $2y$

Length of CA = $4y-1$

Now, we all know that the perimeter of a triangle is sum of all the three sides of triangle.

P(ΔABC) = Length of AB+Length of BC+Length of CA

On substituting the values, we get;

$(y+9)+2y+(4y-1)=29\\y+2y+4y+9-1=29\\7y+8=29\\7y=29-8\\7y=21\\y=\frac{21}{7} =3\ cm$

Length of AB = $y+9=3+9=12\ cm$

Length of BC = $2y=2\times3=6\ cm$

Length of CA = $4y-1=4\times3-1=12-1=11\ cm$

Hence the value of y is 3 cm.

8 0

4 years ago

Margaret bought a pair of pants that were on sale for 30 percent off of the original price. if the original price of pants was $

Monica [59]

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8 0

3 years ago

Read 2 more answers

Help will up-voter!

harina [27]

<h2>Steps:</h2><h3>A.</h3>

For this, plug 4 into the x variable (since 4 is in the x variable of g(x)) and solve as such:

$g(4)=\frac{1}{2}*4+5\\\\g(4)=2+5\\\\g(4)=7$

<u>Your final answer is g(4) = 7.</u>

For this, it's a similar process as A, but you are plugging -10 into the x variable and solving:

$g(-10)=\frac{1}{2}*(-10)+5\\\\g(-10)=-5+5\\\\g(-10)=0$

<u>Your final answer is g(-10) = 0</u>

Similar process as before, but you are plugging 0 for x to solve:

$g(0)=\frac{1}{2}*0+5\\\\g(0)=0+5\\\\g(0)=5$

<u>Your final answer is g(0) = 5.</u>

7 0

3 years ago