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2 years ago

What is the difference between solving inequalities from equations

Mathematics

1 answer:

AVprozaik [17]2 years ago

4 0

Answer:

An equation is a mathematical statement that shows the equal value of two expressions while an inequality is a mathematical statement that shows that an expression is lesser than or more than the other. 2. An equation shows the equality of two variables while an inequality shows the inequality of two variables.

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3 years ago

Read 2 more answers

4. Find the missing values of the Special Right Triangles. Simplify answers. **no decimals **

patriot [66]

Answer:

1)m=9ft and n=10ft

2) p=10cm and r=18cm

3) s=4mi and t=8mi

Step-by-step explanation:

Finding 3rd angle:

F= 180-(90+60)

= 180-150

=30

Now using law of sines to find sides m and n

m/sinD = 5/sinF

m= sin60(5/sin30)

= 8.66

= 9

n/sinE= 5/sin30

n= sin90(5/sin30)

= 10

hence m=9ft and n=10ft

Finding 3rd angle:

F= 180-(90+60)

= 180-150

=30

Now using law of sines to find sides p and r

p/sinF = 21/sinE

p= sin30(21/sin90)

= 10.5

= 10

r/sinD= 21/sin90

r= sin60(21/sin90)

= 18.18

=18

hence p=10cm and r=18cm

Finding 3rd angle:

F= 180-(90+60)

= 180-150

=30

Now using law of sines to find sides s and t

s/sinF = 3√6/sinD

s= sin30(3√6/sin60)

= 4.24

= 4

t/sinE= 3√6/sinD

t= sin90(3√6/sin60)

= 8.48

= 8

hence s=4mi and t=8mi !

4 0

3 years ago

How do I estimate the square root and round to the nearest integer?

Troyanec [42]

The square root of a number $y$ is a number $x$ such that $x^2=y$

So, if a number is a perfect square, its square root is an integer. For example, the square root of 25 is 5, because $5^2=25$ .

If a number is not a perfect square, its square root is not an integer, which means that it is an irrational number, included between two integers.

If you want to find these two integers, you need to find two (consecutive) integers such that the first is "not enough", whereas the second is "too much".

Here's an example, suppose we want to find the square root of 20. We try some integers:

$\left.\begin{array}{cc}1^2 = 1 & \text{Not Enough}\\2^2 = 4 & \text{Not Enough}\\3^2 = 9 & \text{Not Enough}\\4^2 = 16 & \text{Not Enough}\\5^2 =25 & \text{Too Much}\end{array}\right.$

So, when we square 4 is slightly less than 20, and when we square 5 is slightly more than 20. This means that there must exist a number between 4 and 5 that, when squared, is exactly 20.

So, for sure $4 < \sqrt{20} < 5$

In order to round to the nearest integer, we consider that 4^2=16 was 4 units away from the goal (20), while 5^2=25 was 5 units away from the goal. So, 4^2 is nearest to the goal than 5^2, and so we round

$\sqrt{20}\approx 4$

For the record, we have

$\sqrt{20} \approx 4.472135955\ldots$

so our approximation was correct.

3 0

3 years ago