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Leni [432]
2 years ago
6

Heather solved this problem:

Mathematics
1 answer:
Ket [755]2 years ago
4 0

Answer:

A tape diagram. StartFraction part Over whole EndFraction = StartFraction 300 Over 100 EndFraction = StartFraction 75

Step-by-step explanation:

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The band is raising money for their spring trip. they need to raise at
Andrews [41]

The inequality that can be used  to determine the number of boxes of donuts, d, they must sell in order to meet their goal is $1500 ≥ $575 + $5d.

<h3>What is the inequality?</h3>

Here are inequality signs and what they denote:

  • > means greater than
  • < means less than
  • ≥ means greater than or equal to
  • ≤ less than or equal to

Total amount that needs to be raised ≥ amount made at the fruit sale + (profit per box x number of boxes)

$1500 ≥ $575 + $5d

To learn more about inequality, please check: brainly.com/question/5031619

#SPJ1

8 0
2 years ago
Kevin and Randy Muise have a jar containing 80 ​coins, all of which are either quarters or nickels. The total value of the coins
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Answer:

  • 39 quarters and 41 nickels

Step-by-step explanation:

Let the number of quarters be x and nickels be y.

<u>Given:</u>

  • Quarter is 25 cents
  • Nickel is 5 cents
  • Number of coins is 80
  • Total amount is $11.80 = 1180 cents

<u>We have equations:</u>

  • x + y = 80
  • 25x + 5y = 1180

<u>Solve the system by elimination, subtract 5 times the first equation from the second one:</u>

  • 25x + 5y - 5x - 5y = 1180 - 80*5
  • 20x = 780
  • x = 780/20
  • x = 39

<u>Find the value of y:</u>

  • 39 + y = 80
  • y = 80 - 39y = 41

<u>Verify:</u>

  • 25*39 + 5*41 = 975 + 205 = 1180
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2 years ago
Write an equation of the hyperbola given that the center is at (2, -3), the vertices are at (2, 3) and (2, - 9), and the foci ar
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Check the picture below.

so, the hyperbola looks like so, clearly a = 6 from the traverse axis, and the "c" distance from the center to a focus has to be from -3±c, as aforementioned above, the tell-tale is that part, therefore, we can see that c = 2√(10).

because the hyperbola opens vertically, the fraction with the positive sign will be the one with the "y" in it, like you see it in the picture, so without further adieu,

\bf \textit{hyperbolas, vertical traverse axis }&#10;\\\\&#10;\cfrac{(y- k)^2}{ a^2}-\cfrac{(x- h)^2}{ b^2}=1&#10;\qquad &#10;\begin{cases}&#10;center\ ( h, k)\\&#10;vertices\ ( h,  k\pm a)\\&#10;c=\textit{distance from}\\&#10;\qquad \textit{center to foci}\\&#10;\qquad \sqrt{ a ^2 + b ^2}\\&#10;asymptotes\quad  y= k\pm \cfrac{a}{b}(x- h)&#10;\end{cases}\\\\&#10;-------------------------------

\bf \begin{cases}&#10;h=2\\&#10;k=-3\\&#10;a=6\\&#10;c=2\sqrt{10}&#10;\end{cases}\implies \cfrac{[y- (-3)]^2}{ 6^2}-\cfrac{(x- 2)^2}{ b^2}=1&#10;\\\\\\&#10;\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ b^2}=1&#10;\\\\\\&#10;c^2=a^2+b^2\implies (2\sqrt{10})^2=6^2+b^2\implies 2^2(\sqrt{10})^2=36+b^2&#10;\\\\\\&#10;4(10)=36+b^2\implies 40=36+b^2\implies 4=b^2&#10;\\\\\\&#10;\sqrt{4}=b\implies 2=b\\\\&#10;-------------------------------\\\\&#10;\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 2^2}=1\implies \cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 4}=1

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Sometime outiers can have a significant effect on statistics and sometime they don't . Use the following distribution to determi
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3 years ago
Is 3x+15=3(x+5) a infinite solution one solution or no solution
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Answer:

Step-by-step explanation:it is infinite solution because 15 is equal to 15 if it was like 15=13 it is no solution

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2 years ago
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