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Artist 52 [7]
3 years ago
12

The resulting R'ST' is an example of what kind of transformation?

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
4 0

Reflection across y-axis

Imagine folding the paper in half with the y-axis being the crease. the triangles would line up perfectly

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Question: Find the equivalent number.<br><br><br> (I will do brainlisit )
vodomira [7]

Answer:

81/9

9/1

9 is your answer ☺️☺️☺️

3 0
3 years ago
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How many different perfect cubes are among the positive actors of 2021^2021
9966 [12]

Answer:

hope this helps :D

Step-by-step explanation:

Perfect cube factors:

If a number is a perfect cube, then the power of the prime factors should be divisible by 3.

Example 1:Find the number of factors of293655118 that are perfect cube?

Solution: If a number is a perfect cube, then the power of the prime factors should be divisible by 3. Hence perfect cube factors must have

2(0 or 3 or 6or 9)—– 4 factors

3(0 or 3 or 6)  —–  3  factors

5(0 or 3)——- 2 factors

11(0 or 3 or 6 )— 3 factors

Hence, the total number of factors which are perfect cube 4x3x2x3=72

Perfect square and perfect cube

If a number is both perfect square and perfect cube then the powers of prime factors must be divisible by 6.

Example 2: How many factors of 293655118 are both perfect square and perfect cube?

Solution: If a number is both perfect square and perfect cube then the powers of prime factors must be divisible by 6.Hence both perfect square and perfect cube must have

2(0 or 6)—– 2 factors

3(0 or 6) —– 2 factors

5(0)——- 1 factor

11(0 or 6)— 2 factors

Hence total number of such factors are 2x2x1x2=8

Example 3: How many factors of293655118are either perfect squares or perfect cubes but not both?

Solution:

Let A denotes set of numbers, which are perfect squares.

If a number is a perfect square, then the power of the prime factors should be divisible by 2. Hence perfect square factors must have

2(0 or 2 or 4 or 6 or 8)—– 5 factors

3(0 or 2 or 4 or 6)  —– 4 factors

5(0 or 2or 4 )——- 3 factors

11(0 or 2or 4 or6 or 8 )— 5 factors

Hence, the total number of factors which are perfect square i.e. n(A)=5x4x3x5=300

Let B denotes set of numbers, which are perfect cubes

If a number is a perfect cube, then the power of the prime factors should be divisible by 3. Hence perfect cube factors must have

2(0 or 3 or 6or 9)—– 4 factors

3(0 or 3 or 6)  —–  3  factors

5(0 or 3)——- 2 factors

11(0 or 3 or 6 )— 3 factors

Hence, the total number of factors which are perfect cube i.e. n(B)=4x3x2x3=72

If a number is both perfect square and perfect cube then the powers of prime factors must be divisible by 6.Hence both perfect square and perfect cube must have

2(0 or 6)—– 2 factors

3(0 or 6) —– 2 factors

5(0)——- 1 factor

11(0 or 6)— 2 factors

Hence total number of such factors are i.e.n(A∩B)=2x2x1x2=8

We are asked to calculate which are either perfect square or perfect cubes i.e.

n(A U B )= n(A) + n(B) – n(A∩B)

=300+72 – 8

=364

Hence required number of factors is 364.

8 0
3 years ago
Which of the following cannot be the probablity of an event?
ipn [44]

Answer:

Hello There!!

Step-by-step explanation:

I believe the answer is 4,9,0-0.7,1.31,4,9 and 9.The probability of an event if from 0 to 1.

hope this helps,have a great day!!

~Pinky~

8 0
3 years ago
In the number 9440 how many times greater is the 4 marked x more Han 4 marked y
allsm [11]
I dont even know what your asking 
4 0
3 years ago
. 25 points .please help Pythagoras theorem.​
Salsk061 [2.6K]

Answer:

  • 20 cm

Step-by-step explanation:

The bottom leg is divided into equal segments, one of them is b.

It means the bottom leg is b + b = 2b.

<u>According to Pythagorean:</u>

  • 41² = (2b)² + 9²

<u>Solve for b:</u>

  • 1681 = 4b² + 81
  • 4b² = 1681 - 81
  • 4b² = 1600
  • b² = 400
  • b = √400
  • b = 20 cm
4 0
2 years ago
Read 2 more answers
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