5 - 2 times 38 is -71.
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For there to be a region bounded by the two parabolas, you first need to find some conditions on

. The two parabolas must intersect each other twice, so you need two solutions to

You have

which means you only need to require that

. With that, the area of any such bounded region would be given by the integral

since

for all

. Now,

by symmetry across the y-axis. Integrating yields

![=4\left[c^2x-\dfrac{16}3x^3\right]_{x=0}^{x=|c|/4}](https://tex.z-dn.net/?f=%3D4%5Cleft%5Bc%5E2x-%5Cdfrac%7B16%7D3x%5E3%5Cright%5D_%7Bx%3D0%7D%5E%7Bx%3D%7Cc%7C%2F4%7D)



Since

, you have

.
Answer:
Step-by-step explanation:
for 2.2 you would still have 5^2 in brackets still
same kind of error for 2.1
Check the picture below.
make sure your calculator is in Degree mode.
110 I believe is the answer