All categories

2 years ago

Find b in triangle TRG. Please help, I'm not sure how to solve for b.

Mathematics

1 answer:

Marina CMI [18]2 years ago

7 0

Answer:

b=4.9

C. is the correct option.

Step-by-step explanation:

In triangle TGN,

Let <RTG be x

cosx= b/h

or, cosx = 2/a

Again,

In triangle TRG,

cosx = b/h

(for bigger right angled triangle)

cosx = a/(4+2)

cosx = a/6

Now

cosx = 2/a = a/6

or, 2/a = a/6

or, 12 = a²

so, a² = 12

Now,

For TRG,

h² = p²+b²

or, 6² = b² + a²(a²=12)

or, 6² = b² + 12

or, 36 = b² + 12

or, 36 -12 = b²

or, b² = 24

or, b = square root 24

so, b = 4.8989

so, b = 4.9

You might be interested in

Simplify completely quantity 8 x minus 56 over quantity x squared minus 49 divided by quantity x minus 6 over quantity x squared

34kurt

Hello

So the question ask to simplify the said equation. In getting its answer base on that equation you must first factor out each of them then find out the common of them to cancel them out that could lead you to your answer. In my calculation, the answer is D. 8 open parentheses x plus 4 close parentheses over quantity x minus 6. I hope this would help you

Have a nice day

6 0

3 years ago

Expand the polynomial and simplify: (4xy− 1 8 y^2)^2

Vinvika [58]

Answer: $4y^{2}(2x-9y)^{2}$

Step-by-step explanation:

We have the following polynomial:

$(4xy-18y^{2})^{2}$

This is a polynomial of the form $(a-b)^{2}=a^{2}-2ab+b^{2}$ . Following this rule to expand it, we have:

$(4xy)^{2}-2(4xy)(18y^{2})+(18y^{2})^{2}$

$16x^{2}y^{2}-144xy^{3}+324y^{4}$

Applying common factor $4y^{2}$ :

$4y^{2}(4x^{2}-36xy+81y^{2})$

Note the polynomial inside the parenthesis is a perfect square trinomial, which can be factored to $(2x-9y)^{2}$ . Hence, the final simplification is: