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2 years ago

12

Find the circumference of a circle with a radius of 7 centimeters. Use 3.14 as an approximation for pi . Round your answer to th

e nearest whole centimeter. Enter only the number.

1 answer:

givi [52]2 years ago

5 0

Hi this is the answer and explaination

I'm sorry if it's incorrect

hope's it's help

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Solve for x. 5 x − 19 ≤ 1 OR − 4 x + 3 < − 6

k0ka [10]

$5x - 19 \leqslant 1$

change

$\leqslant \: to \: =$

given you

$5x - 19 = 1$

making x the subject by transferring the -19 to the right hand side of the equation

$5x = 19 + 1$

$5x = 20$

dividing through by 5

$\frac{5x}{5} = \frac{20}{5}$

$x = 4$

{ ${x:x \leqslant 4}$ }

also given

$- 4x + 3 < - 6$

change the operation sign to =

$- 4x + 3 = - 6$

$- 4x = - 6 - 3$

$- 4x = - 9$

dividing through by -4

$\frac{ - 4x}{ - 4} = \frac{ - 9}{ - 4}$

$x = \frac{9}{4}$

so the truth set is

{x:x>9/4}.

The < sign changes to > because we divided by a negative number when solving for x

4 0

3 years ago

An engineering scale model shows a church that is 2 inches tall. If the scale is 1 inch = 265 feet, how tall is the actual churc

Nitella [24]

That would be 2 * 265 = 530 feet tall.

4 0

3 years ago

PLZ help me!!!!!!!!!!!!!!!!1

Arte-miy333 [17]

Answer:

80

Step-by-step explanation:

16 × 5 = 80

base × height = area

6 0

2 years ago

Read 2 more answers

mestny [16]

I think one is c And 2 I think is a I just use the desmos graphing calculator at desmos.com

4 0

3 years ago

In Exercise, find the derivative of the function. <br> y = 32e0.23t

TEA [102]

Answer:

$y'=7.36e^{0.23t}$

Step-by-step explanation:

$y=32e^{0.23t}$

take derivative with respect to t

$\frac{dy}{dt} =32\frac{d(e^{0.23t})}{dt}$

derivative of e^t is e^t

derivative of 0.23t is 0.23

$\frac{dy}{dt} =32 \frac{d(e^{0.23t})}{dt}$

Apply chain rule

$\frac{dy}{dt} =32(e^{0.23t})(0.23)$

$y'=7.36e^{0.23t}$

3 0

3 years ago