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lana [24]
2 years ago
11

Solve for n 2/5n+3-7/10n=3/5-3n

Mathematics
1 answer:
LuckyWell [14K]2 years ago
7 0
<h2>The answer is "-\frac{8}{9} \\\\".</h2>

Given:

\to \frac{2}{5}n+3-\frac{7}{10}n=\frac{3}{5}-3n

To find:

n=?

Solution:

\to \frac{2}{5}n+3-\frac{7}{10}n=\frac{3}{5}-3n\\\\\to \frac{2}{5}n-\frac{7}{10}n+3n=\frac{3}{5} -3\\\\\to n(\frac{4-7+30}{10})=\frac{3-15}{5} \\\\\to n(\frac{-3+30}{10})=\frac{3-15}{5} \\\\\to n(\frac{27}{10})=\frac{-12}{5} \\\\\to n=\frac{-12}{5} \times \frac{10}{27} \\\\\to n=-4 \times \frac{2}{9} \\\\\to n=-\frac{8}{9} \\\\

Therefore, the final answer of n is "-\frac{8}{9} \\\\".

Find out more information about solving here:

brainly.com/question/322601

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