Answer:
Cov(X, Y) =0.029.
Step-by-step explanation:
Given that :
The noise in a particular voltage signal has a constant mean of 0.9 V. that is μ = 0.9V ............(1)
Also, the two noise instances sampled τ seconds apart have a bivariate normal distribution with covariance.
0.04e–jτj/10 ............(2)
Having X and Y denoting the noise at times 3 s and 8 s, respectively, the difference of time = 8-3 = 5seconds.
That is, they are 5 seconds apart,
τ = 5 seconds..............(3)
Thus,
Cov(X, Y), for τ = 5seconds = 0.04e-5/10
= 0.04e-0.5 = 0.04/√e
= 0.04/1.6487
= 0.0292
Thus, Cov(X, Y) =0.029.
Answer:
25/6
Step-by-step explanation:
The direct variation tells you that y is proportional to x. That means a reduction by a factor of 5/6 as x changes from 6 to 5 will result in a reduction of y by the same factor.
y = (5/6)(5) = 25/6
Answer:
Step-by-step explanation:
By using regression line calculator,
Equation of the line of best fit,
c). y = 0.74x + 0.03
Here, x = Number of pints
y = Weight in pounds
d). We have to find the weight of 10 pints of the blueberries,
By substituting x = 10 in the equation,
y = 0.74(10) + 0.03
y = 7.4 + 0.03
y = 7.43 pounds
e). If per pound cost of the blueberries = $2.25
By substituting y = 2.25 in the equation,
2.25 = 0.74x + 0.03
x = 
x = $3.00 per pound
Therefore, cost of 10 pounds blueberries = 3 × 10
= $30
The answer would be D if it was 250-6-3n. it wouldnt be A or C because 9 isnt anywhere in the problem and it wouldnt be B because she used 6 peices of paper she didnt just give it to her students
