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Vadim26 [7]
3 years ago
12

If 2.4 g of n2 gas has a volume of 0.40 l and a pressure of 6.6 atm , what is its kelvin temperature?

Chemistry
1 answer:
Nesterboy [21]3 years ago
8 0

To solve for the absolute temperature, we assume ideal gas behaviour so that we use the equation:

PV = nRT

or T = PV / nR

 

So calculating:

T = [6.6 atm * 0.40 L] / [(2.4g / 28g/mol) * 0.08205746 L atm / mol K]

<span>T = 375.35 K</span>

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Part A
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Answer:

ΔG° = -5.4 kJ/mol

ΔG = 873.2 J/mol = 0.873 kJ /mol

Explanation:

Step 1: Data given

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Step 2:

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Part B

ΔG =  ΔG° =RT ln Q

⇒with G° = -5.4 kj/mol = -5400 j/mol

⇒ with R = 8.314 J/K*mol

⇒with T = 298 K

⇒with Q = p(N2O4)/ [ p(NO2) ]² = 1.63/0.36² = 12.577

ΔG = -5400 + 8.314 * 298 * ln(12.577)

ΔG = -5400 + 8.314 * 298 * 2.532

ΔG = 873.2 J/mol = 0.873 kJ/mol

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