MO Diagram of C₂⁻ is shown below,
Bond order is calculated as,
Bond Order = [# of e⁻s in BMO]-[#of e⁻s in ABMO] / 2
Where,
BMO = Bonding Molecular Orbital
ABMO = Anti-Bonding Molecular Orbital
Putting values,
Bond Order = [9]-[4] / 2
Bond Order = 5 / 2
Bond Order = 2.5
A mass of <span>58.44 g hope this helps and plz rate below and thank me on my profile plz</span>
Hello!
This question requires a model -- you'll have to do that yourself. However, I can explain the steps for the process:
• Chlorophyll absorbs the sun's energy.
• The energy is used to split water molecules into hydrogen and oxygen.
• The oxygen is released from the leaves into the atmosphere.
• The hydrogen and carbon dioxide glucose (food) for plants.
If you have any more questions related to this assignment, please let me know!
You could boil away the water, evaporating it, and leaving behind the solute.
For the problem presented, the correct Lewis structure for SrO is <span>[Sr]^+2 + [O]^<span>-2. </span>I am hoping that this answer has
satisfied your query about this specific question. Also, if you have further
questions, please don’t hesitate to ask away.</span>
