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2 years ago

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A student is trying to solve the system of two equations given below: Equation P: y + z = 4 Equation Q: 3y + 7z = 15 Which of th

e following steps can be used to eliminate the y term? A. –3(y + z = 4) B. 3(y + z = 4) C. –1(3y + 7z = 15) D. –3(3y + 7z = 15)

1 answer:

natulia [17]2 years ago

4 0

Look at them
P: 1y
Q: 3y
multiply first equation by -3 becuase 3y-3y=0
-3P
-3(y-z=4) is answer

A is answer

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Step-by-step explanation:

Note: None of options matches with given question.

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Here, First thing you have to observe the nature of roots.

∴ x = - $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i and x = - $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$

∴ [ x+( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i) ][ x+( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i) ]=0

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∴ [ $x^{2}$ + 3x + ( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i)( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i) ] =0

∴ [ $x^{2}$ + 3x + $\frac{9}{4}$ - ( $\frac{\sqrt{3}}{2}$ i)( $\frac{\sqrt{3}}{2}$ i) ] =0

∴ [ $x^{2}$ + 3x + $\frac{9}{4}$ - ( $\frac{3}{4}$ ) $i^{2}$ ] =0

∴ [ $x^{2}$ + 3x + $\frac{9}{4}$ + ( $\frac{3}{4}$ ) ] =0

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