Answer:
c(x)=(x+3)^2+5
Step-by-step explanation:
To complete the square, the same value needs to be added to both sides.
So, to complete the square x^2+6x+9=(x+3)^2 add 9 to the expression
C(x) =x^2 +6x + 9 + 14
Since 9 was added to the right-hand side also add 9 to the left-hand side
C(x) +9= x^2 +6x + 9 + 14
Using a^2 + 2ab + b^2=(a+b)^2, factor the expression
C(x)+9= (x+3)^2 +14
Move constant to the right-hand side and change its sign
C(x)=(x+3)^2 +14 - 9
Subtract the numbers
C(x)= (x+3)^2 +5
Answer:
-18√2
Step-by-step explanation:
i hope it would help u
4⁶ / 4⁸
Since the 'bases' are the same on top and bottom, you can
just subtract the bottom exponent from the top one.
4⁶ / 4⁸
= 4⁶⁻⁸
= 4⁻²
= 1/4²
= 1/16
If the co-vertices are (0, 3) and (0, -3) where x is 0 and y has a value, then y is the minor axis. That means that the x axis is the major axis. Because of what the co-vertices are, the center of the ellipse is at the origin. The formula for an ellipse that has a horizontal major axis is
. The a value will always be larger than the b value, therefore, the a value goes under the coordinate that is the major axis. Here, its the x-axis. a is the distance that the outer edge of the ellipse is from the center. It's 8 units away from the center along the x axis and 3 units along the y axis from the center. So a = 8 and a^2 = 64; b = 3 and b^2 = 9. Our formula then is
I'm not sure what your asking lol but in a box plot you can only see the mean median and mode