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3 years ago

14

PLEASE HELP I NEED ALOT O HELP IM DOING TEST AND NEED HELP John and Julia went out to dinner. Their dinner cost $42.00. They pai

d their waitress a 20% tip. How much did the waitress get in a tip?

2 answers:

seraphim [82]3 years ago

7 0

Answer:

$8.40

Step-by-step explanation:

20% of 42 is 8.4.

slava [35]3 years ago

4 0

Take the 20% turn it into .2 and times it by 42 to get 8.4
42x0.2=8.40

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PLEASE HELP ME GUYS OR I WONT PASS <br>this calculus!!!!

KonstantinChe [14]

Answer:

b. $\displaystyle \frac{1}{2}$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Algebra I</u>

Functions
Function Notation
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$
Exponential Rule [Root Rewrite]: $\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}$ <u> </u>

<u>Calculus</u>

Derivatives

Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

<em /> $\displaystyle H(x) = \sqrt[3]{F(x)}$ <em />

<em />

<u>Step 2: Differentiate</u>

Rewrite function [Exponential Rule - Root Rewrite]: $\displaystyle H(x) = [F(x)]^\bigg{\frac{1}{3}}$
Chain Rule: $\displaystyle H'(x) = \frac{d}{dx} \bigg[ [F(x)]^\bigg{\frac{1}{3}} \bigg] \cdot \frac{d}{dx}[F(x)]$
Basic Power Rule: $\displaystyle H'(x) = \frac{1}{3}[F(x)]^\bigg{\frac{1}{3} - 1} \cdot F'(x)$
Simplify: $\displaystyle H'(x) = \frac{F'(x)}{3}[F(x)]^\bigg{\frac{-2}{3}}$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle H'(x) = \frac{F'(x)}{3[F(x)]^\bigg{\frac{2}{3}}}$

<u>Step 3: Evaluate</u>

Substitute in <em>x</em> [Derivative]: $\displaystyle H'(5) = \frac{F'(5)}{3[F(5)]^\bigg{\frac{2}{3}}}$
Substitute in function values: $\displaystyle H'(5) = \frac{6}{3(8)^\bigg{\frac{2}{3}}}$
Exponents: $\displaystyle H'(5) = \frac{6}{3(4)}$
Multiply: $\displaystyle H'(5) = \frac{6}{12}$
Simplify: $\displaystyle H'(5) = \frac{1}{2}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

5 0

3 years ago

Decrease 1.25 km by 0.6%

Anna35 [415]

Answer:

124250cm, 1242.5m or 1.2425km

Step-by-step explanation:

0.6% = 6/100

6/100 = 0.006

0.006*1.25 = 0.0075

1.25km = 1250m = 125000cm

0.0075km = 7.5m = 750cm

125000 - 750 = 124250

Therefore:

The answer is 124250cm, 1242.5m or 1.2425km

Sub to oTechz :)

4 0

3 years ago

Hello can you please help me posted picture of question

dsp73

The correct answer to your question is 6, option B.

The degree of a polynomial is the highest exponent or power of the variable that is involved in the expression. In the above question we have only one variable which is x, and from the given terms we can see that the highest power of x is 6. So the degree of polynomial is 6. The degree of polynomials helps us to know about the end behavior of the graph.

6 0

4 years ago

Write 3.25 as a mixed number in simplest form.

snow_tiger [21]

3.25 can be re-written as;
=3+0.25
Converting the decimal to a fraction gives;
3+ $\frac{25}{100}$
=Simplify the fraction;
3+ $\frac{1}{4}$
The final answer is;
3 $\frac{1}{4}$

4 0

3 years ago

Read 2 more answers

Alvin is planning to be out of town for the day, so he asks a friend to dog-sit his 3 dogs. Each dog eats 0.5 pounds of food eve

german

Answer:

2 cans

Step-by-step explanation:

Calculate how many pounds he needs for one day:

3(0.5)=1.5 pounds for each day Alvin is gone ( 3 represents his dogs, .5 is each dog's food)

Convert into ounces:

1.5*16=24 ounces for one day

Question: If dog food is sold in 12 oz cans, how many will he need?

24/12=2 cans

Thus, he will need 2 cans

6 0

3 years ago