Answer:
a 75x+165=y
b 75(3)+165=390
c 75x is the cost increasing for each hour
d y-intercept=165, it cost at least 165 for the parts
Step-by-step explanation:
1) 5r*7/15 = 35r/15 = 7r/3
2) 1.2 (w + u/12) = 1.2w + 0.1u
3) 0.2w/2 = 0.1w
4) x +3x/4 + 0.9z = 1.75x + 0.9z
5) 4*( 3y/8 - x/2) = 1.5y -2x
6) 0.6* ( 4w/6 - 5v/18 ) = 2w/5 - 5v/3
Answer:6.1
Step-by-step explanation: the equation is 6n=30.5+n. the first thing you you do is subtract n on both sides which would be 6n-n which gives you 5. the equation now is 5n=30.5. now what you do is divide 5 on both sides so it would be 30.5/5 and that gives you 6.1
Answer:
The launch angle should be adjusted to 30.63°
Step-by-step explanation:
The range of a projectile which is the horizontal distance covered by the projectile can be expressed as;
R =(v^2 sin2θ)/g
Where
R = range
v = initial speed
θ = launch angle
g = acceleration due to gravity
For the case above. When the projectile is launched at angle 13° above the horizontal.
θ1 = 13
R1 = (v^2 sin2θ1)/g
R1 = (v^2 sin26°)/g ....1
For the range to double
R2 = (v^2 sin2θ)/g .....2
R2 = 2R1
Substituting R2 and R1
(v^2 sin2θ)/g = 2 × (v^2 sin26°)/g
Divide both sides by v^2/g
sin2θ = 2sin26
2θ = sininverse(2sin26)
θ = sininverse(2sin26)/2
θ = 30.63°