The amount of pure alcohol that the pharmacist must add to 10 cm of a 10% alcohol solution to strengthen it to a 70% solution is; 20 cm³
<h3>Volume of Solutions</h3>
Let x represent the volume of 100% pure alcohol in cm³ that is required to be added. Thus;
x(100%) + 10%(10 cm³) = 70%(x + 10 cm³)
Multiplying out the bracket gives;
x + (10 × 0.1) = 0.7(x + 10)
⇒ x + 1 = 0.7x + 7
x - 0.7x = 7 - 1
0.3x = 6
x = 6/0.3
x = 20 cm³
In conclusion. the volume of pure alcohol required to be added to 10 cm of a 10% alcohol solution to strengthen it to a 70% solution is 20 cm³
The complete question is;
How much pure alcohol must a pharmacist add to 10 cm of a 10% alcohol solution to strengthen it to a 70% solution? ASAP
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