Answer:
2 square cm
Step-by-step explanation:
Given :
A square is inscribed in a circle whose radius is r = 1 cm
Therefore, the diameter of the circle is 2 r = 2 x 1
= 2 cm.
So the diagonal of the square is 2r.
Using the Pythagoras theorem, we find each of the side of the triangle is .
Therefore, the area of the square is given by
=
Hence the area of the largest square that is contained by a circle of radius 1 cm is 2 cm square.
Y = mx + c
m is the gradient of the graph, for each time you go across 1 x you go up y 'm' times, in your case you go up twice each time you go across once along x
c is the y intercept, the number where the y axis is cut and where you should start drawing your graph
.67, .6, .6, .583, .58, .58, .58, .5, .5
It's 4 with a remainder of 56