Well, let's see . . .
You said that (a) men can dig (c) holes in (b) hours.
So . . . It takes (a) men (b / c) hours to dig one hole.
And . . . It takes One man (a b / c) hours to dig one hole.
Now . . . There are (b) holes to be dug.
It would take one man (a b / c)·(b) = (a b² / c) hours to dig them all.
But if you had 'x' men, it would only take them (c) hours to do it.
So c = (a b² / c) / x
x c = (a b² / c)
x = a b² / c² men .
Now, I lost the big overview while I was doing that,
and just started following my nose through the fog.
So I have to admit that I'm not that confident in the answer.
But gosh durn it. That's the answer I got, and I'm stickin to it.
Rrarrup !
Well! See ,If the endpoints are (x1,y1) & (x2,y2) then mid-point is given by (x1+x2)/2,
(y1+y2)/2
Here in this question endpoints given for the line segment are (-4,2) , (2,4) so we have to find mid-point for x and y co-ordinates by applying above rule.
So, the mid-point we get is (-4+2)/2 , (2+4)/2.
i.e. (-1,3) which lies in 2nd Co-ordinate!
Hope it helps!!
Here is a list of the odd number paired
1+3, 1+5, !+7, and !+9 (there are 4 unique sums - 4, 6,8 and 10)
3+5, 3+7, 3+9 (notice I did not pair 3 with 1 and the the only new sum is 12)
5+7, 5+9 (the only new sum is 14)
7+9 (16 is a new sum)
The sums (no repeats) are 4,6,8,10,12,14 and 16 for a total of seven numbers.
15 divided by 6 2/3 is 2.25. Or 2 1/4. Pick C
Answer:
Step-by-step explanation:
<u>This is an AP with:</u>
- The first term a₁ = 12
- Common difference d = 3
- Number of terms n = 40
<u>Number of the seats:</u>
- Sₙ = 1/2*n(a₁ + aₙ) = 1/2n(2a₁ + (n - 1)d)
- S₄₀ = 1/2*40(12*2 + 39*3) = 2820 seats
<u>Formula of nth term:</u>
- aₙ = a₁ + (n - 1)d
- aₙ = 12 + (n - 1)*3 = 12 + 3n - 3 = 3n + 9
- aₙ = 3n + 9