1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
andrezito [222]
2 years ago
8

What is AC?

Mathematics
1 answer:
Maru [420]2 years ago
3 0
C. 6

Exploration: i got it right.
You might be interested in
6.) -2x + y = -1<br><br> X Y<br> -4<br> -3<br> -2<br> 1<br> 0
MrRa [10]

Answer:

Step-by-step explanation:

i ASSUME THE QUESTION IS TO DETERMINE Y?  

Rearrange the equation  to y = 2x - 1 and solve for each value of x

<u>X</u>  <u>Y</u>

-4  -9

-3  -7

-2  -5

1   1

0  -1

7 0
2 years ago
Help please it’s a quiz
Sidana [21]
......................
3 0
3 years ago
I need help with this
Y_Kistochka [10]

#3 is 40 degrees Clockwise.

6 0
3 years ago
Find the fifth roots of 243(cos 260° + i sin 260°).
Dmitry [639]

Answer:

z1=3 cos (52 + i sin 52)

z2 =3 cos (124 + i sin 124)

z3 = 3 cos (196 + i sin 196)

z4 =3 cos (268 + i sin 268)

z5= 3 cos (340 + i sin 340)

Step-by-step explanation:

To find the fifth roots of 243 (cos 260° + i sin 260°).

z ^ 1/5 = r^1/5 ( cis ( theta + 360 *k)/5)  where k=0,1,2,3,4


So the first root of 243 (cos 260° + i sin 260°)  

is z1 =  243^1/5 ( cis ( 260 + 360 *0)/5)  

          3 cis ( 260/5)

        = 3 cis (52)

        = 3 cos (52 + i sin 52)


The second root of  243 (cos 260° + i sin 260°)  

is z2 =  243^1/5 ( cis ( 260 + 360 *1)/5)  

          3 cis ( 620/5)

        = 3 cis (124)

        = 3 cos (124 + i sin 124)


The third root of  243 (cos 260° + i sin 260°)  

is z3 =  243^1/5 ( cis ( 260 + 360 *2)/5)  

          3 cis ( 980/5)

        = 3 cis (196)

        = 3 cos (196 + i sin 196)


The fourth root of  243 (cos 260° + i sin 260°)  

is z4 =  243^1/5 ( cis ( 260 + 360 *3)/5)  

          3 cis ( 1340/5)

        = 3 cis (268)

        = 3 cos (268 + i sin 268)


The fifth root of  243 (cos 260° + i sin 260°)  

is z5 =  243^1/5 ( cis ( 260 + 360 *4)/5)  

          3 cis ( 1700/5)

        = 3 cis (340)

        = 3 cos (340 + i sin 340)

6 0
3 years ago
12)<br> 4<br> 24<br> 4<br> 36<br> 6<br> find the scale factor
Yakvenalex [24]

Answer:

2

Step-by-step explanation:

4, 24, and 36 are divisible by 4, but there is a 6 and 6 is not divisible by 4. However, all the numbers are divisible by 2.

3 0
3 years ago
Other questions:
  • Find the value of X
    8·1 answer
  • How do I solve 964x83
    5·2 answers
  • H(x) = 4x-2, then which of the following is the solution to h(x)= 3
    7·1 answer
  • 100 points please help
    5·2 answers
  • What is the area of this trapezoid?<br><br> Enter your answer in the box.
    7·2 answers
  • Simplify the expression below 12 divided by (2+1)
    11·1 answer
  • If y varies inversely as x, and y=16 when x=4, find y when x=10
    9·1 answer
  • Which angle in the figure is a right angle?
    15·1 answer
  • Can someone help me please
    10·1 answer
  • If ​P(A)=0.9​, ​P(B)​=0.1, and A and B are​ independent, find​ P(A and​ B).
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!