What is the slope of (1,-5) and (3,-17)

For which distributions is the median the best measure of center? Select each correct answer. Y 20 30 18 25 16 20 14 15+ 12 10+

AURORKA [14]

Answer:

The median is the best measure of center for distributions C and D.

Step-by-step explanation:

The median is the best measure of center for skewed distributions or distributions with outliers because it is a robust statistic, meaning that outliers and skewed data have little effect on the median.

Meanwhile, the mean is a good measure of center for symmetric distributions since it is non-robust.

Answer A has a roughly symmetric distribution, and answer B has a uniform distribution.

Answer C has a left-skewed distribution, and answer D seems to have a right-skewed distribution (since the right tail is longer than the left tail).

Therefore, the median would be the best measure of center for choices C and D.

3 0

3 years ago

What is the length of the red line segment on the number line?

Marianna [84]

Step-by-step explanation:

I think it's D 1 1/2......

8 0

3 years ago

Read 2 more answers

Graph the equation y= 0.5x

marusya05 [52]

Here is the graphed version of equation
Where the slope is 0.5
and y-intercept is 0

6 0

3 years ago

Anthony needs to buy some soda for a school dance. He went to four grocery stores to compare prices. The table below shows the p

viktelen [127]

Answer:

D) store b

Step-by-step explanation:

Because 4 liters is only $6

8 0

3 years ago

Read 2 more answers

A bank is trying to determine which model of safe to install. The bank manager believes that each model is equally resistant to

alexandr402 [8]

Answer:

So on this case the 95% confidence interval would be given by (-1.152;5.152).

$-1.152 < \mu_{safe1}-\mu_{safe2}$

Should we conclude that the average time it takes experts to crack the safes does not differ by model at the 5% significance level?

A) Yes, the 95% confidence interval for ?D contains 0.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution

Let put some notation

x=value for Safe 1 , y = value for Safe 2

x: 103, 90, 64, 120, 104, 92, 145, 106, 76

y: 101, 94, 58, 112, 103, 90, 140, 110, 74

The first step is calculate the difference $d_i=x_i-y_i$ and we obtain this:

d: 2, -4, 6, 8, 1, 2, 5, -4, 2

The second step is calculate the mean difference

$\bar d= \frac{\sum_{i=1}^n d_i}{n}= \frac{18}{9}=2$

The third step would be calculate the standard deviation for the differences, and we got:

$s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1} =4.093$

The next step is calculate the degrees of freedom given by:

$df=n-1=9-1=8$

Now we need to calculate the critical value on the t distribution with 8 degrees of freedom. The value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , so we need a quantile that accumulates on each tail of the t distribution 0.025 of the area.