This is the answer...hope i helped
Answer:
Length = 13
x = 80
Step-by-step explanation:
Question One
Let the width = x
Let the length = x + 5
Area = 104
<u>Equation</u>
Area = L * W
Area = (x+5)*x
<u>Solution</u>
x ( x + 5) = 104 Remove the brackets
x^2 + 5x = 104 Subtract 104 from both sides.
x^2 + 5x - 104 = 104 - 104
x^2 + 5x - 104 = 0 Factor the equation
(x + 13)(x - 8) = 0
Only x - 8 = 0 works
x = 8
The width = 8
The Length = 8 + 5 = 13
Question Two
Draw AP
<BAP = 20o The triangle (APB) is isosceles: 2 sides are radii
<BPA = 180 - 20 - 20 The three angles of a triangle = 180
<BPA = 140 Combine
Similarly <CAP = 140 Go through exactly the same steps.
<BPA + <CAP + X = 360 The total of the 3 angles in the center = 360
140 + 140 + X = 360 Combine
280 + X = 360 Subtract 280 from both sides.
x = 80
P(35) = -9p + 4 = -9(35) + 4 = -315 + 4 = -311
p(28) = 5p - 17 = 5(28) - 17 = 140 - 17 = 123
a + 34d = -311
a + 27d = 123
7d = -434
d = -62
Therefore, the commpm difference is -62.
Distribute and get 2x^2+6x=2x^2+2x-5x-5
add like terms and get 2x^2+6x=2x^2-3x-5
subtract 2x^2 from both sides and get
6x=3x-5
subtract 3x from both sides
3x=5
divide both sides by 3
x=5/3