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2 years ago

I need it ASAP!!!a dot was running on a number line. it travled from 34 to -34. it took 17 minuets. what is the avarage speed?

Mathematics

1 answer:

nirvana33 [79]2 years ago

3 0

Answer:

4 units a minute

Step-by-step explanation:

34 to -34 is 68 units. Divided by 17 is 4, therefore 4 units in 1 minute.

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Which of the following individuals is a good choice to appraise a home?

Shtirlitz [24]

Answer:

A State - appointed professional

Step-by-step explanation:

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2 years ago

A cube is cut in to three parts by vertical slices find the volume of the shaded area The length and width of original is 20 cm

Anni [7]

Answer:

4000 cm^3

Step-by-step explanation:

Note that no image was attached for reference purposes

Step one:

We are given that the original length and width of the cube is 20cm

if the cut part is 10cm

hence the dimension of the cut part is

lenght = 20cm

Width= 20cm

Hieght= 10cm

Step two:

the volume of the cut part will be

Volume= 20*20*10

Volume= 4000 cm^3

7 0

2 years ago

Solve each solution. Check your solution. -32 = -4b

statuscvo [17]

You need to divide-4 on both sides which will get you 8.hope this helps

7 0

3 years ago

Read 2 more answers

Write an equation that represents the distance d and Miles traveled by the monarch butterfly and t days

loris [4]

Complete question :

When the monarch butterfly is migrating to the south, it has an average speed of 80 miles per day. Write an equation that shows the realtionship between the number of days (t) and the distance (in miles) it has traveled (d)

Answer:

d = 80t

Step-by-step explanation:

Given :

Average speed = 80 miles per hour

Distance traveled (in miles) = d

Number of days = t

Equation which shows the Relationship between Number of days and distance traveled :

Recall :

Speed = distance / time

Speed = 80 ; distance = d ; time = t

80 = d/t

80 * t = d

d = 80t

3 0

2 years ago

Find the volume of the solid.

dmitriy555 [2]

In Cartesian coordinates, the region (call it $R$ ) is the set

$R = \left\{(x,y,z) ~:~ x\ge0 \text{ and } y\ge0 \text{ and } 2 \le z \le 4-x^2-y^2\right\}$

In the plane $z=2$ , we have

$2 = 4 - x^2 - y^2 \implies x^2 + y^2 = 2 = \left(\sqrt2\right)^2$

which is a circle with radius $\sqrt2$ . Then we can better describe the solid by

$R = \left\{(x,y,z) ~:~ 0 \le x \le \sqrt2 \text{ and } 0 \le y \le \sqrt{2 - x^2} \text{ and } 2 \le z \le 4 - x^2 - y^2 \right\}$

so that the volume is

$\displaystyle \iiint_R dV = \int_0^{\sqrt2} \int_0^{\sqrt{2-x^2}} \int_2^{4-x^2-y^2} dz \, dy \, dx$

While doable, it's easier to compute the volume in cylindrical coordinates.

$\begin{cases} x = r \cos(\theta) \\ y = r\sin(\theta) \\ z = \zeta \end{cases} \implies \begin{cases}x^2 + y^2 = r^2 \\ dV = r\,dr\,d\theta\,d\zeta\end{cases}$

Then we can describe $R$ in cylindrical coordinates by

$R = \left\{(r,\theta,\zeta) ~:~ 0 \le r \le \sqrt2 \text{ and } 0 \le \theta \le\dfrac\pi2 \text{ and } 2 \le \zeta \le 4 - r^2\right\}$

so that the volume is

$\displaystyle \iiint_R dV = \int_0^{\pi/2} \int_0^{\sqrt2} \int_2^{4-r^2} r \, d\zeta \, dr \, d\theta \\\\ ~~~~~~~~ = \frac\pi2 \int_0^{\sqrt2} \int_2^{4-r^2} r \, d\zeta\,dr \\\\ ~~~~~~~~ = \frac\pi2 \int_0^{\sqrt2} r((4 - r^2) - 2) \, dr \\\\ ~~~~~~~~ = \frac\pi2 \int_0^{\sqrt2} (2r-r^3) \, dr \\\\ ~~~~~~~~ = \frac\pi2 \left(\left(\sqrt2\right)^2 - \frac{\left(\sqrt2\right)^4}4\right) = \boxed{\frac\pi2}$

3 0

1 year ago