Let
X-----------------> number of pansies
y-----------------> number of trees
we know that
x=15*8----------> x=120 pansies
y=8 trees
cost of each trees is----------> $<span>20.75
</span>cost of each pansies is------> $2.50/6------> $5/12
[<span>expression to find Katherine’s final cost]=[cost trees]+[cost pansies]
</span>[cost trees]=y*$20.75
[cost pansies]=x*($5/12)
[expression to find Katherine’s final cost]=y*($20.75)+x*($5/12)
[expression to find Katherine’s final cost]=8*($20.75)+120*($5/12)
[expression to find Katherine’s final cost]=$166+$50
[expression to find Katherine’s final cost]=$216
the answer is
[expression to find Katherine’s final cost]=y*($20.75)+x*($5/12)
[expression to find Katherine’s final cost]=8*($20.75)+120*($5/12)
Katherine’s final cost is $216
Answer:
7.4 x 10^4...............................
<u>Corrected Question</u>
Is the function given by:
continuous at x=4? Why or why not? Choose the correct answer below.
Answer:
(D) Yes, f(x) is continuous at x = 4 because 
Step-by-step explanation:
Given the function:

A function to be continuous at some value c in its domain if the following condition holds:
- f(c) exists and is defined.
exists.
At x=4
Therefore: 
By the above, the function satisfies the condition for continuity.
The correct option is D.
Answer: 5.5%
Step-by-step explanation:
Since the money invested has grown to $8300 and the principal was $600, this means the interest is:
= $8300 - $6500
= $1800
Simple interest = (Principal × Rate × Time)/100
1800 = (6500 × Rate × 5)/100
Cross multiply
1800 × 100 = 32500 × Rate
Rate = 180000/32500
Rate = 5.5%