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3 years ago

To find the distance across a lake, a

Mathematics

2 answers:

Liula [17]3 years ago

7 0

Answer:

608 yard

Step-by-step explanation:

tan 50 degrees =a/510

a=tan 50 degrees x510

=608 yards

Nesterboy [21]3 years ago

6 0

The distance across the lake, a is 611 yards

<h3>Right angle triangle:</h3>

Right angle triangle have one of its angles as 90 degrees. Therefore, the side a can be found using trigonometric ratios,

Therefore,

tan 47° = opposite / adjacent

tan 47° = a / 570

cross multiply

a = 570 tan 47°

a = 570 × 1.07236871002

a = 611.250164714

a = 611 yards

learn more on right triangle here: brainly.com/question/18450490

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I need the area please

Ostrovityanka [42]

The area is 448.5
(13 × 29) + (11 × 13)1/2

5 0

3 years ago

A college-entrance exam is designed so that scores are normally distributed with a mean of 500 and a standard deviation of 100.

Crank

Answer: 1.25

Step-by-step explanation:

Given: A college-entrance exam is designed so that scores are normally distributed with a mean $(\mu)$ = 500 and a standard deviation $(\sigma)$ = 100.

A z-score measures how many standard deviations a given measurement deviates from the mean.

Let Y be a random variable that denotes the scores in the exam.

Formula for z-score = $\dfrac{Y-\mu}{\sigma}$

Z-score = $\dfrac{625-500}{100}$

⇒ Z-score = $\dfrac{125}{100}$

⇒Z-score =1.25

Therefore , the required z-score = 1.25

6 0

3 years ago

A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 380 babies were born, a

Alex Ar [27]

Answer:

The 99% confidence interval estimate of the percentage of girls born is (86.04%, 93.96%). Considering the actual percentage of girls born is close to 50%, the percentage increased considerably with this method, which means that it appears effective.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.